There would be eighteen bonding electrons
Answer:
I think the second space is chemical bonds
1.Start with the number of grams of each element, given in the problem.
2.Convert the mass of each element to moles using the molar mass from the periodic table.
3.Divide each mole value by the smallest number of moles calculated.
4.Round to the nearest whole number. This is the mole ratio of the elements and is.
Answer:
four electrons
Explanation:
Let us attempt to write the electronic configuration of carbon in the ground state. This electronic configuration will now be;
C- 1s2 2s2 2p2
The outermost principal energy level of carbon is the n=2 level which houses the 2s2 and 2p2, making a total of four electrons in the outermost principal energy level of an atom of carbon in the ground state.
For this problem we use the Avogadro's number which is an empirical value that relates the number of particles to the number of moles. Its approximated value is 6.022×10²³ atoms/mole. The solution is as follows:
4.40×10²⁴ aluminum atoms * 1 moles/6.022×10²³ atoms = 7.306
Thus, there are 7.306 moles of aluminum.
