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Zepler [3.9K]
3 years ago
8

A substance that does not dissolve in a solvent is said to be:

Chemistry
1 answer:
Snowcat [4.5K]3 years ago
8 0
A is the I think 83388
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When the population of organisms in an ecosystem is in balance, we consider the ecosystem to be: A. The ecosystem is in successi
krek1111 [17]
The answer is B. Equilibrium means a state in which opposing forces or influences are balanced.
7 0
3 years ago
25<br> #of<br> protons<br> # of<br> neutrons<br> # of<br> electrons
Molodets [167]

Answer:

16

Explanation:

number of electrons should also be 16.

5 0
3 years ago
Air at 25°C with a dew point of 10 °C enters a humidifier. The air leaving the unit has an absolute humidity of 0.07 kg of water
madreJ [45]

Explanation:

The given data is as follows.

         Temperature of dry bulb of air = 25^{o}C

          Dew point = 10^{o}C = (10 + 273) K = 283 K

At the dew point temperature, the first drop of water condenses out of air and then,

        Partial pressure of water vapor (P_{a}) = vapor pressure of water at a given temperature (P^{s}_{a})

Using Antoine's equation we get the following.

            ln (P^{s}_{a}) = 16.26205 - \frac{3799.887}{T(K) - 46.854}

            ln (P^{s}_{a}) = 16.26205 - \frac{3799.887}{283 - 46.854}

                               = 0.17079

                   P^{s}_{a} = 1.18624 kPa

As total pressure (P_{t}) = atmospheric pressure = 760 mm Hg

                                   = 101..325 kPa

The absolute humidity of inlet air = \frac{P^{s}_{a}}{P_{t} - P^{s}_{a}} \times \frac{18 kg H_{2}O}{29 \text{kg dry air}}

                  \frac{1.18624}{101.325 - 1.18624} \times \frac{18 kg H_{2}O}{29 \text{kg dry air}}

                 = 0.00735 kg H_{2}O/ kg dry air

Hence, air leaving the humidifier has a has an absolute humidity (%) of 0.07 kg H_{2}O/ kg dry air.

Therefore, amount of water evaporated for every 1 kg dry air entering the humidifier is as follows.

                 0.07 kg - 0.00735 kg

              = 0.06265 kg H_{2}O for every 1 kg dry air

Hence, calculate the amount of water evaporated for every 100 kg of dry air as follows.

                0.06265 kg \times 100

                  = 6.265 kg

Thus, we can conclude that kg of water the must be evaporated into the air for every 100 kg of dry air entering the unit is 6.265 kg.

3 0
3 years ago
Three examples why cell division is important
kifflom [539]

Answer:

Cell division is important for growth,maintenance of proper chromosome number,wound healing

Explanation:

1 Cell division results in the formation of new cells which further undergo division to form new cells and so forth.Thus many cells are formed which are organized in tissues.Tissues then builds up organs and a number of organs builds up total body.

2 Cell division helps to maintain its chromosome number within the newly formed daughter cells.

3 Division of cells result in the formation of new cells in the site of wound and this accumalation of new cells in the wound region replace damaged and dead cells thus ultimately results in wound healing.

3 0
3 years ago
How many post does it take to support a fence 200 ft long if a post is every 20 feet?
Art [367]
10 because you divide 200 by 20


3 0
3 years ago
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