Answer: ![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D)
of 0.056 M HF solution is 
Explanation:
cM 0 0
So dissociation constant will be:
Give c= 0.056 M and 
= ?
Putting in the values we get:
![[H^+]=c\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Ctimes%20%5Calpha)
![[H^+]=0.056\times 0.0016=8.96\times 10^{-5}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.056%5Ctimes%200.0016%3D8.96%5Ctimes%2010%5E%7B-5%7D)
Thus of 0.056 M HF solution is
Answer:
[H₃O⁺] = 0.05 M & [OH⁻] = 2.0 x 10⁻¹³.
Explanation:
- HNO₃ is completely ionized in water as:
<em>HNO₃ + H₂O → H₃O⁺ + NO₃⁻.</em>
- The concentration of hydronium ion is equal to the concentration of HNO₃:
[H₃O⁺] = 0.05 M.
∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.
<em>∴ [OH⁻] = 10⁻¹⁴/[H₃O⁺] </em>= 10⁻¹⁴/0.05 = <em>2.0 x 10⁻¹³.</em>
The tractor trailer will push the car when they hit so therefore the car will have to greatest change
Answer:
2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)
Explanation:
This question is asking to write and balance an equation between between aqueous sodium carbonate (Na2CO3) and aqueous nitric acid (HNO3). The equation is as follows:
HNO3 (aq) + Na2CO3 (aq) → NaNO3 (aq) + CO2 (g) + H2O (l)
However, this equation is not balanced as the number of atoms of each element must be the same on both sides of the equation. To balance the equation, one will make use of coefficients as follows:
2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)
Answer:
The number of Chlorine atoms in the product is 2.
Explanation:
The law of conservation of mass states that matter can neither be created nor destroyed in a chemical reaction.
The reactants contain one chlorine molecule(
) which has two chlorine atoms.
Then, according to law of conservation of matter, the product must contain two chlorine atoms.
