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navik [9.2K]
4 years ago
14

When applying the process of science which of theseis tested 1.a question, 2.an observation, 3.a conclusion, 4.a prediction

Physics
2 answers:
yKpoI14uk [10]4 years ago
5 0

4. a prediction

Explanation:

According to the scientific method, an experiment is conducted to test a prediction/hypothesis stemming from the previous question.

geniusboy [140]4 years ago
5 0

A conclusion ... usually called a "theory" ... is tested. (3)

One great way to test a conclusion is to follow up on its predictions, and see how they turn out.

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STAR BIRTHS are started when the interstellar matter in gas clouds, such as the Eagle Nebula shown here, compresses and fuses. Irregularities in the density of the gas causes a net gravitational force that pulls the gas molecules closer together. Some astronomers think that a gravitational or magnetic disturbance causes the nebula to collapse. As the gases collect, they lose potential energy, which results in an increase in temperature. As the collapse continues, the temperature increases. The collapsing cloud separates into many smaller clouds, each of which may eventually become a star. The core of the cloud collapses faster than the outer parts, and the cloud begins to rotate faster and faster to conserve angular momentum. When the core reaches a temperature of about 2,000 degrees Kelvin, the molecules of hydrogen gas break apart into hydrogen atoms. Eventually the core reaches a temperature of 10,000 degrees Kelvin, and it begins to look like a star when fusion reactions begin. When it has collapsed to about 30 times the size of our sun, it becomes a protostar. When the pressure and temperature in the core become great enough to sustain nuclear fusion, the outward pressure acts against the gravitational force. At this stage the core is about the size of our sun. The remaining dust envelope surrounding the star heats up and glows brightly in the infrared part of the spectrum. At this point the visible light from the new star cannot penetrate the envelope. Eventually, radiation pressure from the star blows away the envelope and the new star begins its evolution. The properties and lifetime of the new star depend on the amount of gas that remains trapped. A star like our sun has a lifetime of about 10 billion years and is just middle-aged, with another five billion years or so left.</span>
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3 years ago
The Rockets First company needs to hire an engineer to develop a prototype rocket. The company asks several engineers to provide
givi [52]

Answer: I believe this may be Infinity and beyond...i hope this helps you and i apologize if i am wrong.

7 0
3 years ago
Which of the following is NOT NECESSARILY a property of an air mass?
lilavasa [31]

Answer:

a.

Explanation:

a

The property of air mass include

1) it must be large.

2) it must have relatively uniform properties.

3)it must travel as a recognizable entity.

It must have a warm front at its leading edge, is not necessarily a property of an air mass because Not all air masses have a warm front at their leading edge. There are five types of air masses and different types of the front can be developed.

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4 years ago
A simple hydraulic lift is made by fitting a piston attached to a handle into a 3.0-cm diameter cylinder. The cylinder is connec
stiv31 [10]

Answer:

Approximately 3.1 \times 10^4 \; \rm N (assuming that the acceleration due to gravity is g = 9.81\; \rm kg \cdot N^{-1}.)

Explanation:

Let A_1 denote the first piston's contact area with the fluid. Let A_2 denote the second piston's contact area with the fluid.

Similarly, let F_1 and F_2 denote the size of the force on the two pistons. Since the person is placing all her weight on the first piston:

F_1 = W = m \cdot g = 50\; \rm kg \times 9.81 \; \rm kg \cdot N^{-1} =495\; \rm N.  

Since both pistons fit into cylinders, the two contact surfaces must be circles. Keep in mind that the area of a square is equal to \pi times its radius, squared:

  • \displaystyle A_1 = \pi \times \left(\frac{1}{2} \times 3.0\right)^2 = 2.25\, \pi\;\rm cm^{2}.
  • \displaystyle A_2 = \pi \times \left(\frac{1}{2} \times 24\right)^2 = 144\, \pi\;\rm cm^{2}.

By Pascal's Law, the pressure on the two pistons should be the same. Pressure is the size of normal force per unit area:

\displaystyle P = \frac{F}{A}.

For the pressures on the two pistons to match:

\displaystyle \frac{F_1}{A_1} = \frac{F_2}{A_2}.

F_1, A_1, and A_2 have all been found. The question is asking for F_2. Rearrange this equation to obtain:

\displaystyle F_2 = \frac{F_1}{A_1} \cdot A_2 = F_1 \cdot \frac{A_2}{A_1}.

Evaluate this expression to obtain the value of F_2, which represents the force on the piston with the larger diameter:

\begin{aligned}F_2 &= F_1 \cdot \frac{A_2}{A_1} \\ &= 495\; \rm N \times \frac{2.25\, \pi\; \rm cm^2}{144\, \pi \; \rm cm^2} \approx 3.1 \times 10^4\; \rm N\end{aligned}.

6 0
3 years ago
The range of human hearing extends from approximately 20 Hz to 20 000 Hz. Find the wavelengths of these extremes when the speed
soldi70 [24.7K]

Explanation:

Given that,

The range of human hearing extends from approximately 20 Hz to 20 000 Hz. We need to find the wavelengths of these extremes when the speed of sound in air is equal to 338 m/s.

Speed of any wave is given by :

v=f\lambda

\lambda is wavelength of wave

If f = 20 Hz

\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{338}{20}\\\\\lambda=16.9\ m

If f = 20000 Hz

\lambda'=\dfrac{v}{f'}\\\\\lambda'=\dfrac{338}{20000}\\\\\lambda'=0.0169\ m

The smallest wavelength that can be heard is 0.0169 m and the longest wavelength that can be heard is 16.9 m.

7 0
3 years ago
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