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AlekseyPX
3 years ago
11

An airplane with an airspeed of 120 km/h has a heading of 30 degree east of North in a wind that is blowing toward the east at 6

okm/h. What is the speed of the plane relative to the ground
Physics
1 answer:
lesya692 [45]3 years ago
8 0

Answer:

Explanation:

Velocity of plane relative to ground V_pg = ?

Given the velocity in vector form ,

velocity of plane relative to air V_pw = 120 cos30 i + 120sin30j

V_wg = 60 i

V_pg = V_pw +V_wg

= 120 cos30 i + 120sin30j + 60i

= 164 i + 60 j

magnitude

=251 km / h

=

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Answer:

\theta = 106.3 degree

Explanation:

As we know that

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also we can find the magnitude of two vectors as

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now we know the formula of dot product as

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\theta = cos^{-1}(\frac{-14}{50})

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