Answer:
Explanation:
You could try to say how helpful they are what they are and what they do
Complete Question
In an action movie, the villain is rescued from the ocean by grabbing onto the ladder hanging from a helicopter. He is so intent on gripping the ladder that he lets go of his briefcase of counterfeit money when he is 130 m above the water. If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?
Answer:
The speed of the helicopter is 
Explanation:
From the question we are told that
The height at which he let go of the brief case is h = 130 m
The time taken before the the brief case hits the water is t = 6 s
Generally the initial speed of the briefcase (Which also the speed of the helicopter )before the man let go of it is mathematically evaluated using kinematic equation as
Here s is the distance covered by the bag at sea level which is zero
=>
=> 
=> 
The answer is; Irregular.
So the best conductor for electricity is silver.
However because silver is so expensive we use copper which is the next best conductor
Answer:
power drain on an ideal battery, P = 0.017 W
Given:



Since,
and
are in parallel and this combination is in series with
, so,
Equivalent resistance of the circuit is given by:



power drain on an ideal battery, P =
P = 
P = 0.017 W