Answer:
(a). Their speed during that run is 10 m/s.
(b). Their velocity is 6.86 m/s
(c). The final position is at 8.91 m.
Explanation:
Given that,
A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.
Suppose, the distance between 40 yard line and 25 yard line is 20 yard.
(a). We need to calculate their speed during that run
Using formula of speed
![v=\dfrac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bd%7D%7Bt%7D)
Where. d = distance
t = time
Put the value into the formula
![v=\dfrac{18.288}{2}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B18.288%7D%7B2%7D)
during that run
(b). We need to calculate their velocity
Using formula of speed
![v=\dfrac{\Delta d}{\Delta t}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B%5CDelta%20d%7D%7B%5CDelta%20t%7D)
Put the value into the formula
![v=\dfrac{22.86-36.58}{2}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B22.86-36.58%7D%7B2%7D)
![v=-6.86\ m/s](https://tex.z-dn.net/?f=v%3D-6.86%5C%20m%2Fs)
Negative sign shows the direction of motion.
(c). If they kept running at that velocity for another 1.3 seconds,
We need to calculate the final position
Using formula of position
![d=vt](https://tex.z-dn.net/?f=d%3Dvt)
Put the value into the formula
![d=6.86\times1.3](https://tex.z-dn.net/?f=d%3D6.86%5Ctimes1.3)
![d=8.91\ m](https://tex.z-dn.net/?f=d%3D8.91%5C%20m)
Hence, (a). Their speed during that run is 10 m/s.
(b). Their velocity is 6.86 m/s
(c). The final position is at 8.91 m.