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Amiraneli [1.4K]
4 years ago
5

A 1500 kg car rounds a horizontal curve with a radius of 52 m at a speed of 12 m/s. what minimum coefficient of friction must ex

ist between the road and tires to prevent the car from slipping?
Physics
1 answer:
Kitty [74]4 years ago
6 0

Answer:

The minimum coefficient of friction must exist between the road and tires to prevent the car from slipping is μ= 0.28

Explanation:

m= 1500 kg

r= 52m

Vt= 12m/s

g= 9.8 m/s²

Vt= ω * r

ω= Vt/r

ω= 0.23 rad/s

ac= ω²* r

ac= 2.77 m/s²

Fr= m* ac

Fr= 4153.84 N

W= m*g

W= 14700 N

Fr= μ * W

μ= Fr/W

μ=0.28

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Answer:

The period of the system of ladder and woman, T = 2.5 seconds

Explanation:

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The total moment of inertia can be calculated using the equation:

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f = \frac{1}{2\pi } \sqrt{\frac{mgD}{I} } \\f = \frac{1}{2\pi } \sqrt{\frac{48*9.8*1.5}{112.5} }\\f = 0.4

The period of the system of ladder and woman is given by:

T = 1/f

T = 1/0.4

T = 2.5 seconds

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Number 3.

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