The frequency of the wave is 4 Hz
Answer:
Part a)
![v = 7.57 km/h](https://tex.z-dn.net/?f=v%20%3D%207.57%20km%2Fh)
Part b)
North of East
Explanation:
Speed of train towards East = 60 km/h
displacement towards East is given as
![d_1 = 40 km](https://tex.z-dn.net/?f=d_1%20%3D%2040%20km)
now it turns towards 50 degree East of North
so its distance is given as
![d_2 = 20 km(sin50 \hat i + cos50\hat j)](https://tex.z-dn.net/?f=d_2%20%3D%2020%20km%28sin50%20%5Chat%20i%20%2B%20cos50%5Chat%20j%29)
![d_2 = 15.3 \hat i + 12.8 \hat j](https://tex.z-dn.net/?f=d_2%20%3D%2015.3%20%5Chat%20i%20%2B%2012.8%20%5Chat%20j)
then finally it moves towards west for 50 min
![d_3 = -50 \hat i](https://tex.z-dn.net/?f=d_3%20%3D%20-50%20%5Chat%20i)
Now the total displacement of the train is given as
![d = d_1 + d_2 + d_3](https://tex.z-dn.net/?f=d%20%3D%20d_1%20%2B%20d_2%20%2B%20d_3)
![d = (40 + 15.3 - 50)\hat i + 12.8 \hat j](https://tex.z-dn.net/?f=d%20%3D%20%2840%20%2B%2015.3%20-%2050%29%5Chat%20i%20%2B%2012.8%20%5Chat%20j)
![d = 5.3\hat i + 12.8 \hat j](https://tex.z-dn.net/?f=d%20%3D%205.3%5Chat%20i%20%2B%2012.8%20%5Chat%20j)
now total time duration of the motion is given as
![T = 40 min + 20 min + 50 min](https://tex.z-dn.net/?f=T%20%3D%2040%20min%20%2B%2020%20min%20%2B%2050%20min%20)
![T = 1.83 h](https://tex.z-dn.net/?f=T%20%3D%201.83%20h)
now average velocity is given as
![v_{avg} = \frac{5.3\hat i + 12.8\hat j}{1.83}](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%20%5Cfrac%7B5.3%5Chat%20i%20%2B%2012.8%5Chat%20j%7D%7B1.83%7D)
![v_{avg} = 2.89\hat i + 6.99\hat j](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%202.89%5Chat%20i%20%2B%206.99%5Chat%20j)
Part a)
magnitude of the average velocity is given as
![v = \sqrt{v_x^2 + v_y^2}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7Bv_x%5E2%20%2B%20v_y%5E2%7D)
![v = \sqrt{2.89^2 + 6.99^2}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2.89%5E2%20%2B%206.99%5E2%7D)
![v = 7.57 km/h](https://tex.z-dn.net/?f=v%20%3D%207.57%20km%2Fh)
Part b)
Direction of the velocity is given as
![tan\theta = \frac{v_y}{v_x}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7Bv_y%7D%7Bv_x%7D)
![tan\theta = \frac{6.99}{2.89}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7B6.99%7D%7B2.89%7D)
North of East
The answer is Balance. hopei helped? ahahahaha