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3 years ago

How do i solve this function? (Number 28)

Mathematics

1 answer:

ikadub [295]3 years ago

7 0

For ever input, there is one ouput

it means we can't repeat the same x with a different y
but repeats of y's are allowed

pick any numbers that haven't been used as an input

-5 isn't taken
0 is taken
11 is taken
-1 is taken
2 is not taken
17 is taken

so -5 and -1 or A and D are the answers

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Which equation has x=4 as the solution

dedylja [7]

Answer:

are you looking for example?

Step-by-step explanation:

If so,

X + 3 = 7

4 0

3 years ago

If ƒ(x ) = 3x + 1 and ƒ -1 = , then ƒ -1(7) =

Elden [556K]

F(x) = 3x + 1

let f(x) = y

y = 3x + 1

y - 1 = 3x

3x = y - 1

x = (y - 1)/3

From y = f(x), x = f⁻¹(y)

x = (y - 1)/3

f⁻¹(y) = (y - 1)/3

f⁻¹(7) = (7 - 1)/3 = 6/3 = 2

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3 years ago

The supreme choice pizza at Pete's Pizza contains 2 different meats and 4 different vegetables. The customer can select any one

lara31 [8.8K]

Answer:

80 possible combinations

Step-by-step explanation:

each crust can have a choice of 2 different types of meat and 4 different types of vegetables

if crust1 has four different meat options and two types of meat on each pizza then there are six options possible for the meat on each crust. Now you have 8 veggies and each pizza can have 4 veggies. then there are 56 different veggie combinations.(4+6+56)= 80

6 0

3 years ago

Find the distance between the points of intersection of the graphs of the functions.

Viefleur [7K]

Answer:

Find the value of x and y in coordinate form, that'll be the point of intersection.

Question 1

${ \rm{y = {x}^{2} - 3x + 4 }} \\ { \boxed{ \tt{but \: y = x + 1 \: }}} \\ \\ { \rm{(x + 1) = {x}^{2} - 3x + 4 }} \\ \\ { \rm{ {x}^{2} - 4x + 3 = 0 }} \\ \\ { \rm{(x - 3)(x - 1) = 0}} \\ \\ { \boxed{ \rm{x_{1} = 3 \: \: and \: \: x _{2} = 1}}} \\ \\ { \boxed{ \tt{remember \: y = x + 1}}} \\ \\ { \rm{y _{1} = 4 \: \: and \: \: y _{2} = 2 }}$

Therefore, points of intersection are two

Answer:  (3, 4) and (1, 2)

Question 2:

Following the steps as in question 1

${ \rm{y = {x}^{2} - 4}} \\ \\{ \rm{2x - 4 = {x}^{2} - 4}} \\ \\ { \rm{ {x}^{2} = 2x }} \\ \\ { \boxed{ \rm{x = 2}}} \\ { \tt{remember : \: y = 2x - 4 }} \\ { \boxed{ \rm{y = 0}}}$

Answer: (2, 0)

7 0

3 years ago

Read 2 more answers

Help.please ASAP will mark brainliest !!!

kupik [55]

The answer is D because if you continue the pattern the bottom number would have to be 8 and the top would have to be 7!!

8 0

3 years ago