Let <em>s</em> be the plane's speed in still air and <em>w</em> the wind speed. Then
<em>s</em> - <em>w</em> = (6060 km)/(6 h) = 1010 km/h
<em>s</em> + <em>w</em> = (12,150 km)/(9 h) = 1350 km/h
Adding these equations together eliminates <em>w</em> and lets you solve for <em>s</em> :
(<em>s</em> - <em>w</em>) + (<em>s</em> + <em>w</em>) = 1010 km/h + 1350 km/h
2<em>s</em> = 2360 km/h
<em>s</em> = 1180 km/h
Yes it is because it’s parallel and it appear to be correct
The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
Read more on average of integers;
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Answer:
9
Step-by-step explanation:
-4(6x+3)= -12(x+10)
<u><em>Let's do the first part:</em></u>
-4(6x+3)
<em>**distribute**</em>
-4 x 6x = -24x; -4 x 3 = -12 ->>> -24x - 12
<u><em>Let's do the second part:</em></u>
-12(x+10)
<em>**distribute**</em>
-12 x x = -12x; -12 x 10 = -120 ->>> -12x -120
-24x -12 = -12x - 120
<em>**Move variable to the left-hand side and change its sign**</em>
-24x +12x -12 = -120
-12x - 12 = -120
-12x = 108
x = 108/-12
x=9
