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Zinaida [17]
4 years ago
14

How many milliliters of a 0.80 M sucrose solution contain each of the following number of grams? The molar mass of sucrose (C12H

22O11) is 342.3 g/mol.
a. 7.45 g




b. 17.0 mg
Chemistry
1 answer:
OlgaM077 [116]4 years ago
7 0

 The  number of Ml  of 0.80 M sucrose solution  that contain

(A) 7.45 g are  27.25 Ml


 <u>calculation</u>

volume= moles /molarity

molarity = 0.80 M which is the same as  0.80 mol/l

moles=  mass/molar mass

=  7.45 g/ 342.3 g/mol =0.0218 moles

volume is therefore  = 0.0218 moles / 0.80 mol/L=0.02725 L

convert into ml  by multiplying  by 1000

= 27.25  ml


<h3>   <u> question b</u></h3>

volume  = moles/molarity

molarity =  0.80 M = 0.80 Mol/L

moles =mass/molar mass

mass 17.0 mg convert into  g by diving  by 1000=0.017 g


moles is therefore  = 0.017 g/ 342.3 g/mol = 4.97 x10^-5 moles


volume =  (4.97 x 10^-5 moles)  /0.8  mol /l=6.21 x10^-5 L

= 6.21 x10^-5  x 1000 =0.0621 Ml




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