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1 year ago

nitric acid (63 g) and sodium hydroxide (60 g) are mixed. determine how many grams of water will form.

Chemistry

1 answer:

kenny6666 [7]1 year ago

8 0

The water of 17.99 g forms when 63g of HNO₃ mixes with60g of NaOH

When nitric acid and sodium hydroxide are mixed, a neutralization reaction takes place, with the salt created by the two substances and water serving as the reaction result. The chemical reaction to the statement in this instance is:

HNO₃ + Na(OH) ⇒ NaNO₃ + H₂O

It is determined whether there is one limiting reagent and one in excess, or if both react entirely, by calculating the molar masses of the reagents and using the masses provided by the statement to compute the ratio in which these compounds are combined.

• The formula for HNO₃'s molar mass is 3xmO + mH + mN, or 3x15.99g + 1g + 14g = 62.97 g/mol.

• The formula for Na(OHmolar )'s mass is: mO + mH + mNa = 15.99g + 1.00g + 22.99g = 39.98 g / mol.

Nitric acid is immediately apparent to be the limiting reagent.

Since there are initially 60 g of hydroxide, some of it will stay unreacted because the balanced equation's stoichiometric ratio states that 1 mole of acid reacts with 1 mole of hydroxide. As a result, 63 g of HNO3 react with 40 g of hydroxide. This proves that acid is the limiting reagent, and calculations to determine how much water will form must be based on this substance.

For 63g of HNO₃ 18g of water is formed. Then,

for 62.97 g of HNO₃,

= 18 g x 63 g equals/62.97 g

= 17.99 g of water.

As a result, the correct response is that 17.99 g of water will form.

To know more about neutralization, click below:

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1.56 mol H₂

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3.120 mol Si * $\frac{1molMg_3(Si_2O_5)_2(OH)_2}{4molSi}$ = 0.78 mol Mg₃(Si₂O₅)₂(OH)₂

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3 years ago

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3 years ago

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An ionic bond forms when atoms blank electrons

8_murik_8 [283]

Answer:

An ionic bond forms when atoms transfer electrons.

Explanation:

Ionic bonds are formed when atoms transfer electrons. (In contrast, covalent bonds are formed when atoms share electrons.)

There's a distinction between the two: when two atoms react to form an ionic bond, one atom would completely lose one electron, while the other would completely gain that electron. The atom that loses the electron becomes a positively-charged ion called a cation, whereas the atom that gains the electron becomes a negatively-charged ion called an anion.

For example, consider the reaction between a sodium $\rm Na$ atom and a chlorine $\rm Cl$ atom: $\rm Na + Cl \to NaCl$ .

When the sodium atom and the chlorine atom encounter, the sodium atom would lose one electron to form a positively-charged sodium ion, $\rm Na^{+}$ . The chlorine atom would gain that electron to form a negatively-charged chlorine ion $\rm Cl^{-}$ .

These two ions will readily attract each other because of the opposite electrostatic charges on them. This electrostatic attraction (between two ions of opposite charges) is an ionic bond.

Overall, it would appear as if the sodium $\rm Na$ atom transferred an electron to the chlorine $\rm Cl$ atom to form an ionic bond.

In contrast, when two atoms react to form a covalent bond, they share electrons without giving any away completely. Therefore, it is possible to break certain covalent bonds apart (using a beam of laser, for example) and obtain neutral atoms.

On the other hand, when an ionic bond was broken, the result would be two charged ions- not necessarily two neutral atoms. The electron transfer could not be reversed by simply breaking the bond.

For example, when table salt $\rm NaCl$ is melted (at a very high temperature,) the ionic bond between the sodium ions and chloride ions would (mostly) be broken. However, doing so would only generate a mixture of $\rm Na^{+}$ and $\rm Cl^{-}$ ions- not sodium and chlorine atoms.

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3 years ago

A solution was found to have a 15.6 % transmittance at 500 nm, its wavelength of maximum absorption, using a cell with a path le

Gnesinka [82]

For the absorbance of the solution in a 1.00 cm cell at 500 nm is mathematically given as

A’ = 0.16138

<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>

Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069

Generally, the equation for the Beer’s law is mathematically given as

A = ε*c*l

0.8069 = ε*c*(5.00 )

ε*c = 0.16138 cm-1

then for when ε*c is constant

l’ = 1.00

A’ = (0.16138 cm-1)*(1.00 cm)

A’ = 0.16138

In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is

A’ = 0.16138