<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.
<u>Explanation:</u>
We are given:
Initial pressure of air = 769.0 torr
Final pressure of air = 717.1 torr
Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr
To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
where,
P = pressure of the gas = 51.9 torr
V = Volume of the gas = 2.20 L
T = Temperature of the gas = 292 K
R = Gas constant = ![62.364\text{ L. Torr }mol^{-1}K^{-1}](https://tex.z-dn.net/?f=62.364%5Ctext%7B%20L.%20Torr%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D)
n = number of moles of oxygen gas = ?
Putting values in above equation, we get:
![51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol](https://tex.z-dn.net/?f=51.9torr%5Ctimes%202.20L%3Dn%5Ctimes%2062.364%5Ctext%7B%20L.%20Torr%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D%5Ctimes%20292K%5C%5C%5C%5Cn%3D%5Cfrac%7B51.9%5Ctimes%202.20%7D%7B62.364%5Ctimes%20292%7D%3D0.0063mol)
To calculate the mass from given number of moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
Moles of oxygen gas = 0.0063 moles
Molar mass of oxygen gas = 32 g/mol
Putting values in above equation, we get:
![0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g](https://tex.z-dn.net/?f=0.0063mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20oxygen%20gas%7D%7D%7B32g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20oxygen%20gas%7D%3D%280.0063mol%5Ctimes%2032g%2Fmol%29%3D0.202g)
Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.