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yKpoI14uk [10]
4 years ago
6

Plz I really need help plz I'm begging you

Mathematics
2 answers:
Charra [1.4K]4 years ago
7 0
I Suck at math but I got 42 for "x"
Crazy boy [7]4 years ago
6 0

do this:

1.add 52+3x

2.divide180 by the first answer

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PLEASE HELP
photoshop1234 [79]
Parameters of functions are the independent variable(s). e.x. y = 2x /\  x is the independent <span> variable (the parameter).</span>
6 0
3 years ago
A student's grade for the four quarters are 95, 83, 91, and 85. What does the student need to earn on the final exam to have an
gulaghasi [49]

Answer:

The least score the student can get is 71 to get an overall B average at the end of the year.

Step-by-step explanation:

Let the score she needs to get be = x

We now have to take the mean of all the five subjects <em>(including x)</em> and equate it to the least score she can have to get a B grade.

Let us take the least score the student needs to get a B grade to be 85

Mean of all 5 scores =

\frac{95+83+91+85+x}{5}=85

\frac{354+x}{5} =85

354+x = 425

x = 71

The least score the student can get is 71 to get an overall B average at the end of the year.

3 0
3 years ago
What is a 3 2/3 model example?
Annette [7]

I don't have an exact model but this site can help you.


https://learnzillion.com/lesson_plans/7928-use-models-for-division-of-fractions-by-fractions/


I hope this helps you in your studies and have an awesome day!


8 0
3 years ago
Use these properties to rewrite 7/4 + 1/2 + 5/3 + 1/3 + 1/4 + 1/2 in a way that makes the addition easier. Explain how your chan
Reptile [31]
It makes the addition easier if you combine like terms like the two 1/2s and then make them all have the denominator of 12 (changing the numerators to equal it out)
3 0
3 years ago
Read 2 more answers
The length of a rectangle is 5959 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
lorasvet [3.4K]

Length: 2w + 59

width: w

diagonal: (2w + 59) + 2  = 2w + 61

Length² + width² = diagonal²

(2w + 59)² + (w)² = (2w + 61)²

(4w² + 118w + 3481) + w²  = 4w² + 122w + 3721

5w² + 118w + 3481 = 4w² + 122w + 3721

w² + 118w + 3481 = 122w + 3721

w² - 4w + 3481 = 3721

w² - 4w - 240 = 0

a = 1, b = -4, c = -240

w = [-(b) +/- \sqrt{(b)^{2}  - 4(a)(c) }]/2(a)

 = [-(-4) +/- \sqrt{(-4)^{2}  - 4(1)(-240) }]/2(1)

   =  [4 +/- \sqrt{(16  + 960) }]/2        

  = [4 +/- \sqrt{(976) }]/2  

  = [2 +/- 4\sqrt{(61) }]/2  

  = 1 +/- 2\sqrt{(61) }

since width cannot be negative, disregard  1 - 2√61

w = 1 + 2√61  ≈ 16.62

Length: 2w + 59  =  2(1 + 2√61) + 59  = 2 + 4√61 + 59  =  61 + 4√61  ≈ 92.24

Answer: width = 16.62 in, length = 92.24 in

7 0
3 years ago
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