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Verdich [7]
3 years ago
5

Two elements in the second transition series (y through cd ) have three unpaired electrons in their 3+ ions. what elements fit t

his description?

Chemistry
2 answers:
Tanzania [10]3 years ago
7 0
Molybdenum and Rhodium, I believe. All of the elements in these 2 groups follow unusual orbital filling rules.

Hope this helped!
kotykmax [81]3 years ago
4 0

Answer: The elements that have 3 unpaired electrons in their +3 oxidation states are Molybdenum and Palladium.

Explanation: The elements in the second transition series are:

Yttrium (Y), Zirconium (Zr), Niobium (Nb), Molybdenum (Mo), Technetium (Tc), Ruthenium (Ru), Rhodium (Rh), Palladium (Pd), Silver (Ag) and Cadmium (Cd).

The electronic configuration of these elements are:

Y=[Kr]5s^24d^1             ;      Y^{3+}=[Kr]

Zr=[Kr]5s^24d^2           ;      Zr^{3+}=[Kr]4d^1

Nb=[Kr]5s^14d^4           ;      Nb^{3+}=[Kr]4d^2

Mo=[Kr]5s^14d^5           ;     Mo^{3+}=[Kr]4d^3

Tc=[Kr]5s^14d^6            ;     Tc^{3+}=[Kr]4ds^4

Ru=[Kr]5s^14d^7            ;     Ru^{3+}=[Kr]4d^5

Rh=[Kr]5s^14d^8            ;     Rh^{3+}=[Kr]4d^6

Pd=[Kr]5s^04d^{10}          ;     Pd^{3+}=[Kr]4d^7

Ag=[Kr]5s^14d^{10}           ;     Ag^{3+}=[Kr]4d^8

Cd=[Kr]5s^24d^{10}          ;     Cd^{3+}=[Kr]4d^9

From the above configurations of the elements in their +3 ionic state, the elements having 3 unpaired electrons are Molybdenum and Palladium.

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6 0
3 years ago
Which of the following acids is in household vinegar? A nitric acid hydrochloric acid C fluoric acid D acetic acid
Free_Kalibri [48]

Answer: Out of the given options acetic acid is in household vinegar.

Explanation:

Household vinegar is the one that is commonly used in our home while cooking a number of dishes.

The common name of vinegar is acetic acid and its chemical formula is CH_{3}COOH.

For example, vinegar (acetic acid) is used while making noodles.

Thus, we can conclude that out of the given options acetic acid is in household vinegar.

7 0
3 years ago
How do I revise for a science test due tomorrow? I haven’t revised but I have to get a good score. Anyone please help!
Komok [63]

Answer:

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7 0
2 years ago
50.0 ml of 0.010m naoh was titrated with 0.50m hcl using a dropper pipet. if the average drop from the pipet has a volume of 0.0
creativ13 [48]

25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.

The equation of the reaction is;

NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)

We can use the titration formula;

CAVA/CBVB = NA/NB

CA= concentration of acid

VA = volume of acid

CB = concentration of base

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

CB = 0.010 M

VB = 50.0 ml

CA = 0.50 M

VA = ?

NA = 1

NB = 1

Substituting values;

CAVANB = CBVBNA

VA =  0.010 ×  50.0 × 1/ 0.50 × 1

VA = 1 ml

Since the total volume of acid used is 1 ml and each drop contains 0.040 ml

The number of drops required is 1ml/0.040 ml = 25 drops

Learn more: brainly.com/question/1527403

4 0
3 years ago
Where does the rest of the energy “lost” go? <br> (In food webs)
Blizzard [7]

Explanation:

The rest of the energy is passed on as food to the next level of the food chain. The figure at the left shows energy flow in a simple food chain. Notice that at each level of the food chain, about 90% of the energy is lost in the form of heat.

3 0
2 years ago
Read 2 more answers
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