Given li2, c2, s2, and cl2, which of these species is paramagnetic? view available hint(s) g.com
1 answer:
Compounds containing unpaired electrons are paramagnetic in nature, while compounds containing no unpaired electrons are diamagnetic in nature.
Attached is the molecular orbital diagram of S2 molecule. For the MOT diagram it can be seen that S2 molecule has two unpair electron in two π* orbital. Due to this, it is paramagnetic in nature.
In contrast to this, Li2, C2 and Cl2 have no unpaired electrons. Hence they are diamagnetic in nature.
Attached is the molecular orbital diagram of S2 molecule. For the MOT diagram it can be seen that S2 molecule has two unpair electron in two π* orbital. Due to this, it is paramagnetic in nature.
In contrast to this, Li2, C2 and Cl2 have no unpaired electrons. Hence they are diamagnetic in nature.
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Answer:
0.879 mg
Explanation:
To solve this problem we need to use the definition of ppm:
- ppm = μg solute / g solution
With the above information in mind we can calculate the micrograms of lead using the concentration (13.97 ppm) and mass of solution (62.9 g):
- μg lead = 13.97 ppm * 62.9 g
- μg lead = 878.713 μg
Finally we convert μg to mg:
- 878.713 μg *
= 0.879 mg of lead