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2 years ago

Given li2, c2, s2, and cl2, which of these species is paramagnetic? view available hint(s) g.com

Chemistry

1 answer:

Lady_Fox [76]2 years ago

7 0

Compounds containing unpaired electrons are paramagnetic in nature, while compounds containing no unpaired electrons are diamagnetic in nature.

Attached is the molecular orbital diagram of S2 molecule. For the MOT diagram it can be seen that S2 molecule has two unpair electron in two π* orbital. Due to this, it is paramagnetic in nature.

In contrast to this, Li2, C2 and Cl2 have no unpaired electrons. Hence they are diamagnetic in nature.

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John rode 3150 m at an average speed of 350 m/min.If he had ridden at average of 375 m/min instead. How much sooner would it hav

Svet_ta [14]

Explanation:

Given that:

Distance traveled = 3150m

Average speed = 350m/min

Suggested speed = 375m/min

Unknown:

Time = ?

Solution:

Speed is the rate of change of distance with time.

it is mathematically expressed as;

speed = $\frac{distance }{time}$

Initial time using speed 350m/min can be calculated by making time the subject of the formula;

time taken = $\frac{distance }{speed}$

time taken at speed of speed of 350m/min = $\frac{3150}{350}$ = 9min

to seconds = 9 x 60 = 540 seconds

time taken at speed of 375m/min = $\frac{3150}{375}$ = 8.4min

to seconds = 8.4 x 60 = 504 seconds.

It could have taken 504 seconds sooner saving 36 seconds.

learn more:

Speed brainly.com/question/10177389

#learnwithBrainly

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3 years ago

What happens when molecular compounds melt?

Harman [31]

Molecules arranged in regular pattern changes into an irregular pattern

6 0

3 years ago

Read 2 more answers

A gas occupies a volume of 1.00 L at 25.0°C. What volume will the gas occupy at 1.00 x10^2 °C?

Leno4ka [110]

Answer : The volume of gas occupy at $1.00\times 10^2^oC$ is, 1.25 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=1.00L\\T_1=25.0^oC=(25.0+273)K=298K\\V_2=?\\T_2=1.00\times 10^2^oC=((1.00\times 10^2)+273)K=373K$

Putting values in above equation, we get:

$\frac{1.00L}{298K}=\frac{V_2}{373K}\\\\V_2=1.25L$

Therefore, the volume of gas occupy at $1.00\times 10^2^oC$ is, 1.25 L

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musickatia [10]

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ycow [4]

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