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DanielleElmas [232]
4 years ago
13

A student is given a stock solution of 1.00 M NaCl in water. They are asked to make 5 mL of 0.0500 M NaCl. How much of the stock

solution should they dilute to 5 mL to make the correct concentration?
a) 10.0 mL
b) 55.5 mL
c) 1.00 mL
d) 35.3 mL
e) 27.8 mL
Chemistry
1 answer:
Harrizon [31]4 years ago
3 0

Answer:

The answer to your question is None of your answers is correct, maybe the data are wrong.

Explanation:

Data

Concentration 1 = C1 = 1 M

Volume 2 = 5 ml

Concentration 2 = 0.05 M

Volume 1 = x

To solve this problem use the dilution formula

             Concentration 1 x Volume 1 = Concentration 2 x Volume 2

Solve for Volume 1

              Volume 1 = (Concentration 2 x Volume 2)/ Concentration 1

Substitution

              Volume 1 = (0.05 x 5) / 1

Simplification

              Volume 1 = 0.25/1

Result

               Volume 1 = 0.25 ml

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Mixing of salt is physical change.

Explanation:

Mixing of salt is physical change because no chemical reaction occur between them. Sand is non polar while salt is polar.

Physical Change:                                                                                              

The changes that occur only due to change in shape or form but their chemical or internal composition remain unchanged.

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Explanation:

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