3x<3+4x<2
3x-3<4x<-1
-3<x<-1
9514 1404 393
Answer:
- there are no points higher than a maximum; no points lower than a minimum
- average rate of change is the slope of a straight line connecting the points of interest.
Step-by-step explanation:
1. A point on a graph is a maximum if there are no points on the graph that are higher.
A point on a graph is a minimum if there are no points on the graph that are lower.
Sometimes you're interested in a "local" maximum or minimum. In that case, the "no points higher/lower" rule refers to points in the immediate vicinity of the one of interest.
Sometimes you're interested in a maximum or minimum on an interval. In that case, the rule applies to points contained within the interval. (The maximum or minimum may be at the end of the interval.)
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2. Average rate of change is defined over some interval. That is, you are given the end points of the interval of interest. The average rate of change is the slope of a straight line between those end points. The slope formula applies:

Answer:
There is a 3/5 chance of the first ball being white, and a 3/10 chance the second one is black.
Step-by-step explanation:
There are 5 balls, of which 3 are white, so you have a 3/5 chance of the first one being white. Then you have 2 white and 2 black balls. There is a 2/4 chance of picking a black ball. Multiply 3/5 and 2/4 to get 6/20, or 3/10 for choosing a white ball then a black ball.
Answers:
x = 6 and P = 128
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Explanation:
The tangents CT and CU are equal to each other. The rule is that tangent segments that meet at a common point are the same length.
Let's solve for x
CT = CU
3x = 18
x = 18/3
x = 6
Because CT = 18, this makes BC = BT+TC = 12+18 = 30
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For similar reasoning as mentioned earlier, we can say tangents BT and BV are the same length. This means BV = 12.
Segment CD = 52 and CU = 18, which makes UD = CD-CU = 52-18 = 34
From there, we can say segment DV = 34 also. This leads to BD = BV+VD = 12+34 = 46
Triangle BCD has the three sides
The perimeter is
P = sum of the three sides
P = (side1)+(side2)+(side3)
P = BC + CD + BD
P = 30+52+46
P = 82+46
P = 128
Note: Consider we need to find the vertices of the triangle A'B'C'
Given:
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).
To find:
The vertices of the triangle A'B'C'.
Solution:
If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

Using this rule, we get



Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).