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4 years ago

What is the acceleration of an arrow that has a mass of 0.1 kg and a force of 9 N?

Physics

1 answer:

VikaD [51]4 years ago

7 0

F = ma

f/m = a

9/0.1 = 90 m/s^2

so the answer is 90 m/s^2

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A negative charge feels a force when stationary in an electric field. moving parallel to an electric field. moving parallel to a

Yuki888 [10]

Answer:

stationary in an electric field.

moving perpendicular to a magnetic field.

moving perpendicular to an electric field.

Explanation:

Negative charge: In physics, the term "negative charge" is defined as a phenomenon that consists of a surplus or different electrons in any field i.e magnetic or electric field.

However, the correct answer in the question above, would be:

"stationary in an electric field".

"moving perpendicular to a magnetic field".

"moving perpendicular to an electric field".

8 0

3 years ago

___________________ and ___________________________ are two main types of waves.

iris [78.8K]

Answer:

its A

Explanation:

6 0

4 years ago

Which feature in this graph represents:

Rom4ik [11]

Answer:

almost 100% positive its B but dont take me up on it

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3 years ago

A neutron star is an extremely dense, rapidly spinning object that results from the collapse of a massive star at the end ofits

Westkost [7]

Answer:

(a). The rotational inertia is $5.72\times10^{39}\ kg m^2$

(b). The magnitude of the magnetic torque is $3.20\times10^{35}\ N-m$

Explanation:

Given that,

Mass of neutron $M_{n}= 13M_{s}$

Density of neutron $\rho=4.8\times10^{17}\ kg/m^3$

(a). We need to calculate the rotational inertia

Using formula of rotational inertia for sphere

$I=\dfrac{2}{5}MR^2$ ...(I)

We know that,

$\rho=\dfrac{M}{V}$

Put the value of volume

$\rho=\dfrac{3M_{n}}{4\pi R^3}$

$R^2=(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}$

Put the value of R in equation (I)

$I=\dfrac{2}{5}\times M_{n}\times(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}$

Put the value into the formula

$I=\dfrac{2}{5}\times(13\times2\times10^{30})^{\frac{5}{3}}\times(\dfrac{3}{4\pi\times(4.8\times10^{17})})^{\frac{2}{3}}$

$I=5.72\times10^{39}\ kg m^2$

The rotational inertia is $5.72\times10^{39}\ kg m^2$ .

(b). We need to calculate the magnitude of the magnetic torque

Using formula of torque

$\tau=I\times \alpha$

Put the value into the formula

$\tau=5.72\times10^{39}\times5.6\times10^{-5}$

$\tau=3.20\times10^{35}\ N-m$

The magnitude of the magnetic torque is $3.20\times10^{35}\ N-m$

Hence, (a). The rotational inertia is $5.72\times10^{39}\ kg m^2$

(b). The magnitude of the magnetic torque is $3.20\times10^{35}\ N-m$

4 0

3 years ago

Suppose you want to whisper to the student next to you in class, what must you remember to do with your vocal cords

Juliette [100K]

You have to lower you vocals

7 0

4 years ago