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BabaBlast [244]
4 years ago
15

___________________ and ___________________________ are two main types of waves.

Physics
1 answer:
iris [78.8K]4 years ago
6 0

Answer:

its A

Explanation:

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Which would show an example of how physical changes are reversible? cutting a gold bar in two pieces and then putting the pieces
arlik [135]

Melting tin and then cooling it into a mold is an example of reversible physical changes.

<u>Explanation:</u>

         When an object undergoes a change in size, state, or shape and not in their chemical compositions referred to as physical change. But chemical change occurs as a result of the change in substances composition. It also forms a new one by the combination/ breakage of one or more objects.

         In the case of making gold cube into two pieces, there is no possibility of getting the original state again even the physical change happens. Match burning and relighting and sodium plus chlorine forming table salt show chemical change. But in tin melting and cooling it to form mold is the physical change i.e changes in state(liquid to solid) and are reversible too.

6 0
3 years ago
Read 2 more answers
Explain what happens with the light when you see black and white opaque objects
maksim [4K]

Answer:

When white light strikes a colored opaque object, some colors of light are absorbed and some are reflected. ... Some of the colors are absorbed and some are reflected. When white light shines on a white object, all colors are reflected. When white light strikes a black object, all colors are absorbed.

Explanation:

7 0
3 years ago
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A typical atomic polarizability is 1 × 10-40 (C·m)/(N/C). If the q in p = qs is equal to the proton charge e, what charge separa
Alenkasestr [34]

Answer:

s = 6.25 10⁻²² m

Explanation:

Polarizability is the separation of electric charges in a structure, in the case of the atom it is the result of the separation of positive charges in the nucleus and the electrons in their orbits, macroscopically it is approximated by

                p = q s

               s = p / q

let's calculate

              s = 1 10⁻⁴⁰ / 1.6 10⁻¹⁹

              s = 0.625 10⁻²¹ m

              s = 6.25 10⁻²² m

We see that the result is much smaller than the size of the atom, therefore this simplistic model cannot be taken to an atomic scale.

6 0
3 years ago
Allen Aby sets up an Atwood Machine and wants to find the acceleration and the tension in the string. Please help him. Two block
Vitek1552 [10]

<u>Answers:</u>

In order to solve this problem we will use Newton’s second Law, which is mathematically expressed after some simplifications as:

<h2>F=ma   (1) </h2>

This can be read as: The Net Force F of an object is equal to its mass m multiplied by its acceleration a.

We will also need to <u>draw the Free Body Diagram of each block</u> in order to know the direction of the acceleration in this system and find the Tension T of the string (<u>See figure attached).  </u>

We already know<u> m_{2} is greater than m_{1}</u>, this means the weight of the block 2 P_{2} is greater than the weight of the block 1 P_{1}; therefore <u>the acceleration of the system will be in the direction of P_{2}</u>, as shown in the figure attached.

We also know by the information given in the problem that <u>the pulley does not have friction and has negligible mass</u>, and <u>the string is massless</u>.

This means that the tension will be the same along the string regardless of the difference of mass of the blocks.

Now that we have the conditions clear, let’s begin with the calculations:

1) Firstly, we have to find the weight of each block, in order to verify that block 2 is heavier than block 1.

This is done using equation (1), where the force of the weight P is calculated using the <u>acceleration of gravity</u> g=9.8\frac{m}{s^{2}}  acting on the blocks:


<h2>P=mg   (2) </h2>

<u>For block 1: </u>

P_{1}=m_{1}g   (3)

P_{1}=1.5kg(9.8\frac{m}{s^{2}})    

<h2>P_{1}=14.7N   (4) </h2>

<u>For block 2: </u>

P_{2}=m_{2}g   (5)

P_{2}=2.4kg(9.8\frac{m}{s^{2}})    

<h2>P_{2}=23.52N      (6) </h2>

Then, we are going to <u>find the acceleration a of the whole system: </u>

F_{r}=P_{1}+P_{2}   (7)

<h2>P_{1}+P_{2}=(m_{1}+m_{2})a   (8) </h2>

Where the Resulting Force F_{r}  is equal to the sum of the weights P_{1} and P_{2}.  

In the figure attached, note that P_{1} is in opposite direction to the acceleration a, this means it must <u>have a negative sing</u>; while P_{2} is in the same direction of a.

Here we only have to isolate a from equation (8) and substitute the values according to the conditions of the system:

-14.7N+23.52N=(1.5kg+2.4kg)a  

8.82N=(3.9kg)a  

Then:

a=\frac{8.82N }{3.9kg}  

<h2>a=2.26\frac{m}{ s^{2}}  </h2><h2>This is the acceleration of the system. </h2>

2) For the second part of the problem, we have to find the tension T of the string.

We can choose either the Free Body Diagram of block A or block B to make the calculations, <u>the result will be the same</u>.  

Let’s prove it:

For m_{1}

we see in the free body diagram that the <u>acceleration is in the same direction of the tension of the string</u>, so:

F_{r}=T-P_{1}   (9)

T-P_{1}=m_{1}a   (10)

T-14.7N=(1.5kg)( 2.26\frac{m}{ s^{2}})    

Then;

<h2>T=18.09N   This is the tension of the string </h2><h2> </h2>

For m_{2}

we see in the free body diagram that the acceleration is in opposite direction of the tension of the string and must <u>have a negative sign,</u> so:

F_{r}=T-P_{2}   (9)

T-P_{2}=m_{2}a   (10)

T-23.52N=(2.4kg)(-2.26\frac{m}{ s^{2}})    

Then;

<h2>T=18.09N    This is the same tension of the string </h2>

6 0
3 years ago
Explain the four major classification of tissues
icang [17]
1.Epithelium- lines and covers surfaces
2. Connective tissue- protect, support, and bind together
3. Muscular tissue- produces movement
4. Nervous tissue- receive stimuli and conduct impulses
Hope i helped u :)


6 0
3 years ago
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