The light energy that falls on a square meter of ground over the course of a typical sunny day is about 20 MJ. The average rate
1 answer:
Answer:
86MJ
Explanation:
THE TOPIC FROM WHICH THE QUESTION IS OBTAINED IS WORK, ENERGY AND POWER
- Power is defined as the time rate of doing work.
- Power =
- If the energy use is in joules and the time is in seconds, then power is a measure of watts. 1watt = 1 joule per second.
- According to the question, we need to find how much energy does one house use during each 24 hour day ( Already given time = 24hours) when the average rate of electric energy consumption in one house is 1.0 kW ( we have been given power = 1kW).
- Power = 1kW = 1 × 10³W
- Time = 24hours = 24 ×3600 = 86400seconds.
- It is important we have our time in seconds so as to be consistent with unit and dimension
Power =
1 × 10³W =
- Energy used =1 × 10³W × 86400
- Energy used = 86400000J = 86.4 ×
W = 86.4MJ
The question requested the answer in 2 significant figures and the answer is 86MJ
You might be interested in
The concept of this question can be well understood by listing out the parameters given.
- The mass of the block = 51 g = 51 × 10⁻³ kg
- The distance of the block from the table = 30 cm
- Length of the spring = 30 cm
The purpose is to determine the spring constant.
Let us assume that the two blocks are Block A and Block B.
At point A on block A, the initial velocity on the block is zero
i.e. u = 0
We want to determine the time it requires for Block A to reach the table. The can be achieved by using the second equation of motion which can be expressed by using the formula.
From the above formula,
The distance (S) = 30 cm; we need to convert the unit to meter (m).
- Since 1 cm = 0.01 m
- Then, 30cm = 0.3 m
The acceleration (g) due to gravity = 9.8 m/s²
∴
inputting the values into the equation above, we have;
By dividing both sides by 4.9, we have:
However, block B comes to an instantaneous rest on point C. This is achieved by the dropping of the block on the spring. During this process, the spring is compressed and it bounces back to oscillate in that manner. The required time needed to get to this point C is half the period, this will eventually lead to the bouncing back of the block with another half of the period, thereby completing a movement of one period.
By applying the equation of the time period of a simple harmonic motion.
where the relation between time (t) and period (T) is:
T = 2t
T = 2(0.247)
T = 0.494 seconds
By making the spring constant k the subject of the formula:
Therefore, we conclude that the spring constant as a result of instantaneous rest caused by the compression of the spring is 8.25 N/m.
Learn more about simple harmonic motion here:
brainly.com/question/17315536?referrer=searchResults
