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ehidna [41]
3 years ago
13

Classify each of the following word equations as a synthesis, decomposition, single displacement, or double displacement reactio

n.
Will give brainliest.

Chemistry
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer:

12: This is decomposition because nitrogen triiodide is breaking apart.

13: This is double displacement because the elements in the compounds are "switching".

14: This is synthesis because the water and carbon dioxide are combining.

15: This is also synthesis because the hydrogen and oxygen are combining.

16: This is single displacement because the sodium is "switching" the element it's bonding with.

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Calculate the number of calories in 1/4 lbs of margarine
dezoksy [38]

The answer is 814.5 :

There is 3258 calories in one pound of margarine (according to google)

one-fourth= 0.25

0.25*3258= 814.5 calories

3 0
3 years ago
An unknown gas effuses at a rate 0.797 times that of nitrogen at the same temperature. what is the molar mass of the unknown gas
kicyunya [14]
<span>mass B/molar mass A = (rate A/rate B)^2. we know our unknown gas (A) effuses at .797 times our known gas (B) so rate A/rate B = .797 so 0.797^2 = 28 / molar mass A Molar mass A = 28 / 0.635 = 44.09 g / mole Molar mass is 44.09 g/mol</span>
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3 years ago
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An unknown substance has been shown to have weak covalent bonds.
Anton [14]

Answer:

Low melting point.

Explanation:

We cannot link the pH of a substance from it bonds directly.

Ionic compounds have strong ionic bonds but we cannot say that they will have high or low pH.

High conductivity is a feature of ionic compounds generally (also metals)

low melting point means the bonds are weak so they can be weak covalent bonds.

Low flammability is not related to bonding.

6 0
3 years ago
6. A 50-year-old sample of Strontium-90 is found. The half-life of strontium is 29
Gnesinka [82]

Answer:

the sample has mass of 50mg initially

Explanation:

https://youtu.be/ietdukGMG5c

8 0
3 years ago
In a coffee-cup calorimeter, 1.60 g of NH4NO3 was mixed with 75.0 g of water at an initial temperature of 25.008C. After dissolu
jekas [21]

Answer:

Explanation:

mass of the solution m = 1.6 + 75 = 76.6 g

fall in temperature = 25 - 23.34 = 1.66°C

heat absorbed = mass x specific heat x fall in temperature

= 76.6 x 1.66 x 4.18

= 531.5 J .

= .5315 kJ .

mol weight of ammonium nitrate = 80 g

heat absorbed by 1.6 g = .5315 kJ

heat absorbed by 80 g or one mole = 26.575 kJ

enthalpy change ΔH = +26.575 kJ

b )

enthalpy of hydration = 2630 kJ / mol

lattice energy = enthalpy of hydration + enthalpy change

= 2630 + 26.575

= 2656.575 kJ  .

7 0
3 years ago
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