Answer:
1.44 L
Explanation:
Since 25 is constant it is no use. Now, rearrange the gas formula. You should get...
P1V1/T2=P2V2T1
Next, rearrange to fit the problem. You should get...
V2=P1V1/P2
Fill in our values and solve. You should get 1.44 L
We can check this by knowing that P and V at constant T have an inverse relationship. Hence, this is correct.
- Hope that helps! Please let me know if you need further explanation.
Electrons in atoms can act as our charge carrier, because every electron carries a negative charge. If we can free an electron from an atom and force it to move, we can create electricity.
The density of metal block in grams per cubic centimeter is 10.70 g/cm³.
Given,
Mass of metal block = 5.16 lb
1 lb = 453.592 g
5.26 lb = 2340.536 g
The volume of metal block = 14 in 3
1 in = 2.5 cm
1 in 3 = 15.625 cm³
14 in 3 = 218.75 cm³
Density is defined as the mass per unit volume of a substance. Or, it is the ratio of mass to the volume of the substance.
As we know,
Density = mass/volume
Or, density = 2340.536 / 218.75
Or, density = 10.70 g/cm³
Therefore, the density of the metal block is 10.70 g/cm³.
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Answer:
Explanation:
Molar mass of Argon
= 35.96755 x .00337 + 37.96272 x .00063 + 39.96240 x .99600
= .12121 + .0239165 + 39.80255
= 39.95
Molar mass of silicon
27.97693 x .9223 + 28.97649 x .0467 + 29.97376 x .0310
= 25.803 + 1.35320 + .929
= 28.08
b )
No of atoms of Si in 78.2 g = 78.2 x 6.02 x 10²³ / 28.08
= 16.76 x 10²³ .
c )
42 Ar / 40 Ar = 1.05006
42 Ar / 39.95 = 1.05006
42Ar = 41.95
2 )
C₁₆H₁₅F₂N₃O₄S
Mol weight = 16 x 12 + 1 x 15 + 2 x 19 + 3 x 14 + 4 x 16 + 32
= 192 + 15 + 38 + 42 + 64+ 32
= 383
No of molecules = .078 x 6.02 x 10²³ / 383
= 1.226 x 10²⁰ molecules .
Answer: The empirical formula for the given compound is 
Explanation : Given,
Percentage of C = 38.8 %
Percentage of H = 16.2 %
Percentage of N = 45.1 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of C = 38.8 g
Mass of H = 16.2 g
Mass of N = 45.4 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen = 
Moles of Nitrogen = 
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.
For Carbon = 
For Hydrogen = 
For Oxygen = 
Step 3: Taking the mole ratio as their subscripts.
The ratio of C : H : N = 1 : 5 : 1
Hence, the empirical formula for the given compound is 
