3.) <br><br> Please answer this question!

Before drawing 3,3,4,4-tetramethylhexane, answer the following questions.

erma4kov [3.2K]

The answers to your questions are 6 and 4. Trust me my friend.

Hope this helps! God bless
-vf

4 0

4 years ago

A. draw the structure of the tetrahedral intermediate initially formed in the reaction shown. you do not have to consider stereo

julsineya [31]

The reaction is shown below, Acid protonates the carbonyl oxygen and makes the carbonyl carbon more electrophilic. Water attacks on activated carbonyl group and forms a tetrahedral intermediate.

Intermediate:
Structure of Intermediate is shown both in 2-D and 3-D (below attached).

Carbonyl group is regenerated with the elimination of ethanol.

Reaction is as below, The final product is carboxylic acid.

4 0

3 years ago

If 1.332 mol of C4H10 are reacted with 6.504 mol of O2, how many mol of the excess reagent will remain unreacted? 2 C4H10 + 13 O

Luden [163]

Answer: The number of moles of excess reagent remain unreacted will be, 6.004 moles.

Explanation : Given,

Moles of $C_4H_{10}$ = 1.332 mol

Mass of $O_2$ = 6.504 mol

First we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2$

From the balanced reaction we conclude that

As, 13 mole of $O_2$ react with 1 mole of $C_4H_{10}$

So, 6.504 moles of $O_2$ react with $\frac{6.504}{13}=0.5003$ moles of $C_4H_{10}$

From this we conclude that, $C_4H_{10}$ is an excess reagent because the given moles are greater than the required moles and $O_2$ is a limiting reagent and it limits the formation of product.

Number of moles remain unreacted = 6.504 mol - 0.5003 mol = 6.004 mol

Therefore, the number of moles of excess reagent remain unreacted will be, 6.004 moles.

5 0

4 years ago

Which particles are referred to as subatomic particles located in the nucleus

damaskus [11]

The subatomic particles that are located in the nucleus are both neutrons and protons!

4 0

3 years ago

Solid aluminum hydroxide reacts with a solution of hydrobromic acid. Write a balanced molecular equation and a balanced net ioni

lora16 [44]

Answer:

$Al(OH)_{3}(s)+3H^{+}(aq.)+3Br^{-}(aq.)\rightarrow Al^{3+}(aq.)+3Br^{-}(aq.)+3H_{2}O(l)$

$Al(OH)_{3}(s)+3H^{+}(aq.)\rightarrow Al^{3+}(aq.)+3H_{2}O(l)$

Explanation:

Aluminium hydroxide ( $Al(OH)_{3}$ ) is a base and hydrobromic acid (HBr) is a strong acid.

Hence an acid-base reaction occurs between $Al(OH)_{3}$ and HBr

Balanced molecular equation:

$Al(OH)_{3}(s)+3HBr(aq.)\rightarrow AlBr_{3}(aq.)+3H_{2}O(l)$

Balanced total ionic equation:

$Al(OH)_{3}(s)+3H^{+}(aq.)+3Br^{-}(aq.)\rightarrow Al^{3+}(aq.)+3Br^{-}(aq.)+3H_{2}O(l)$

Balanced net ionic equation:

$Al(OH)_{3}(s)+3H^{+}(aq.)\rightarrow Al^{3+}(aq.)+3H_{2}O(l)$

(net ionic equation is written by removing common ions present in both side of total ionic equation)

5 0

3 years ago

3.) Please answer this question!