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IgorC [24]
3 years ago
14

3.) Please answer this question!

Chemistry
1 answer:
alina1380 [7]3 years ago
4 0

Answer:

umm no

Explanation:

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Before drawing 3,3,4,4-tetramethylhexane, answer the following questions.
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4 years ago
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A. draw the structure of the tetrahedral intermediate initially formed in the reaction shown. you do not have to consider stereo
julsineya [31]
The reaction is shown below, Acid protonates the carbonyl oxygen and makes the carbonyl carbon more electrophilic. Water attacks on activated carbonyl group and forms a tetrahedral intermediate.

Intermediate:
                    Structure of Intermediate is shown both in 2-D and 3-D (below attached). 

Carbonyl group is regenerated with the elimination of ethanol.

Reaction is as below, The final product is carboxylic acid.

4 0
3 years ago
If 1.332 mol of C4H10 are reacted with 6.504 mol of O2, how many mol of the excess reagent will remain unreacted? 2 C4H10 + 13 O
Luden [163]

Answer: The number of moles of excess reagent remain unreacted will be, 6.004 moles.

Explanation : Given,

Moles of C_4H_{10} = 1.332 mol

Mass of O_2 = 6.504 mol

First we have to calculate the limiting and excess reagent.

The balanced chemical equation is:  

C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2

From the balanced reaction we conclude that

As, 13 mole of O_2 react with 1 mole of C_4H_{10}

So, 6.504  moles of O_2 react with \frac{6.504}{13}=0.5003 moles of C_4H_{10}

From this we conclude that, C_4H_{10} is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Number of moles remain unreacted = 6.504 mol - 0.5003 mol = 6.004 mol

Therefore, the number of moles of excess reagent remain unreacted will be, 6.004 moles.

5 0
4 years ago
Which particles are referred to as subatomic particles located in the nucleus
damaskus [11]
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4 0
3 years ago
Solid aluminum hydroxide reacts with a solution of hydrobromic acid. Write a balanced molecular equation and a balanced net ioni
lora16 [44]

Answer:

Al(OH)_{3}(s)+3H^{+}(aq.)+3Br^{-}(aq.)\rightarrow Al^{3+}(aq.)+3Br^{-}(aq.)+3H_{2}O(l)

Al(OH)_{3}(s)+3H^{+}(aq.)\rightarrow Al^{3+}(aq.)+3H_{2}O(l)

Explanation:

Aluminium hydroxide (Al(OH)_{3}) is a base and hydrobromic acid (HBr) is a strong acid.

Hence an acid-base reaction occurs between Al(OH)_{3} and HBr

Balanced molecular equation:

Al(OH)_{3}(s)+3HBr(aq.)\rightarrow AlBr_{3}(aq.)+3H_{2}O(l)

Balanced total ionic equation:

Al(OH)_{3}(s)+3H^{+}(aq.)+3Br^{-}(aq.)\rightarrow Al^{3+}(aq.)+3Br^{-}(aq.)+3H_{2}O(l)

Balanced net ionic equation:

Al(OH)_{3}(s)+3H^{+}(aq.)\rightarrow Al^{3+}(aq.)+3H_{2}O(l)

(net ionic equation is written by removing common ions present in both side of total ionic equation)

5 0
3 years ago
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