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IgorC [24]
3 years ago
14

3.) Please answer this question!

Chemistry
1 answer:
alina1380 [7]3 years ago
4 0

Answer:

umm no

Explanation:

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Carnegie Development stages
Darya [45]

Answer:

Stage 1: 1 days.

Stage 2: 2-3 days.

Stage 3: 4-5 days.

Stage 4: 6 days.

Stage 5 (a-c): 7-12 days.

Stage 6: c. 17 days.

Stage 7: c. 19 days.

Stage 8: c. 23 days.

7 0
2 years ago
How many moles are present in 2.126 g of H2O2 ?
Vinil7 [7]

Answer:

molecular weight of H2O2 or grams. This compound is also known as Hydrogen Peroxide. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles H2O2, or 34.01468 grams.

1 grams H2O2 is equal to 0.029399071224542 mole.

1 grams H2O2 to mol = 0.0294 mol

10 grams H2O2 to mol = 0.29399 mol

20 grams H2O2 to mol = 0.58798 mol

30 grams H2O2 to mol = 0.88197 mol

40 grams H2O2 to mol = 1.17596 mol

50 grams H2O2 to mol = 1.46995 mol

100 grams H2O2 to mol = 2.93991 mol

200 grams H2O2 to mol = 5.87981 mol

6 0
2 years ago
Read 2 more answers
Single and double replacement reactions practice WS CuCl2 +<br> F2 »<br> CuF2<br> +<br> Cl2
Lapatulllka [165]
CuCl2+F2—>CuF2+Cl2.
This is a single replacement because there is one compound and one element. Picture Cu as ‘A’ Cl2 as ‘B’ and F2 as ‘C.’ So AB+C—>AC+B. A and B “broke up” and that resulted to A going with C to create the compound CuF2 leaving Cl2 alone.
7 0
2 years ago
The freezing point of ethanol, CH3CH2OH, is -117.300 °C at 1 atmosphere. Kf(ethanol) = 1.99 °C/m
MAXImum [283]

Answer : The molecular weight of this compound is 891.10 g/mol

Explanation :  Given,

Mass of compound = 12.70 g

Mass of ethanol = 216.5 g

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=i\times T_f\times\frac{\text{Mass of compound}\times 1000}{\text{Molar mass of compound}\times \text{Mass of ethanol}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure ethanol = -117.300^oC

T_f = temperature of solution = -117.431^oC

K_f = freezing point constant of ethanol = 1.99^oC/m

i = van't hoff factor = 1   (for non-electrolyte)

m = molality

Now put all the given values in this formula, we get

(-117.300)-(-117.431)=1\times 1.99^oC/m\times \frac{12.70g\times 1000}{\text{Molar mass of compound}\times 216.5g}

\text{Molar mass of compound}=891.10g/mol

Therefore, the molecular weight of this compound is 891.10 g/mol

7 0
2 years ago
Record the volume of the liquid in the graduated cylinder. The volume of the liquid is
mario62 [17]

Answer:

53

Explanation:

5 0
3 years ago
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