Answer:
[KCl] = 1.2 M
Explanation:
We need to complete the reaction:
2KCl(aq) + Pb(NO₃)₂(aq) → 2KNO₃(aq) + PbCl₂(s)↓
By stoichiomety we know that 1 mol of chloride needs 1 mol of nitrate to react:
Let's find out the moles of nitrate, we have:
Molarity = mol/volume(L)
We convert the volume → 30 mL . 1L/1000mL = 0.030L
Molarity . volume(L) = moles → 0.400 M . 0.030L = 0.012 moles
Therefore, we can make a rule of three.
1 mol of nitrate reacts with 2 moles of chloride
Then, 0.012 moles of nitrate must react with (0.012 . 2) / 1 = 0.024 moles of KCl
We convert the volume from mL to L → 20 mL . 1L /1000mL = 0.020L
Molarity = mol /volume(L) → 0.024 mol /0.020L = 1.2 M
Dalton gathers evidence for the existence of atoms by measuring the masses of elements after compounds are formed.
<u>Explanation</u>:
- John Dalton accumulated proof for the presence of atoms by estimating the majority of components that responded to frame mixes. All components are made out of molecules. All particles of a similar component have a similar mass, and atoms of various components have various masses. Mixes contain atoms of more than one component.
-
Dalton did numerous investigations that gave proof to the presence of particles. For instance, He researched pressure and different properties of gases, from which he induced that gases must comprise of little, singular particles that are in steady, arbitrary movement.
Answer:
C2H5OH has a greater boiling point.
Explanation:
It is a bigger molecule than C2H6.
In order to balance this, you have to count
each element where the elements in the reactants side and the product side
should have equal number of molecules. The balanced reaction is as follows:
KOH + H3PO4 = KH2PO4 +H2O
Answer:
1. 
2. 
Explanation:
Hello,
1. In this case, since the volume of the rock is obtained via the difference between the volume of the cylinder with the water and the rock and the volume of the cylinder with the water only:
Thus, the density turns out:
2. In this case, given the density and mass of aluminum we can compute its volume as follows:
Moreover, as the volume is also defined in terms of width, height and length:
The height is computed to be:
Best regards.
