Answer:
The wavelengths at which resonance occurs are proportional to the length of the instrument, so you can play different notes by changing the length. In general the larger the instrument the longer the wavelength of the fundamental and the lower the frequency range of the instrument.
Explanation:
excitatory amino acids are the amino acids helps in transformation of neurotransmitters or it helps in transmission of synapsis rapidly in brain of mammal. EAA known to be neurotransmitters for Central nervous system.
Excitatory amino acids count may vary from 50’s to 100’s. They are mostly composed of non-protein- amino acids obtained from algae or fungi.
The possible EAAs are Glutamate (Glu) and Aspartate which act as excitatory neurotransmitters in the brain. They get released from neurons where they induce excitation via metabotropic Glu receptors.
Both glutamate and aspartate having excitatory effect on neurotransmission whereas Gama-amino butyric acid having inhibitory effect on neurotransmission.
Thus, the statement ‘neurotransmitters are chemical brother of gaba’ is indicating the complementary effect of each other.
Answer:
In the criss-cross method, the numerical value of the ion charge of the two atoms are crossed over, which becomes the subscript of the other ion. Using this technique, we will write the chemical formula of the given compounds.
Criss cross the absolute values to give Al2O3. To find the formula for magnesium oxide:- The oxidation number of Mg is +2 and oxygen is -2. Criss cross the absolute values to give Mg2O2In this example there is a common factor of 2 so divide by 2 to give MgO.
<u>Given information:</u>
Mass of NaCl (m) = 87.75 g
Volume of solution (V) = 500 ml = 0.5 L
Molar mass of NaCl (M) = 58.44 g/mol
<u>To determine:</u>
The molarity of NaCl solution
<u>Explanation:</u>
Molarity is defined as the number of moles of solute(n) dissolved per liter of solution (V)
i.e. M = moles of solute/liters of solution = n/V
Moles of solute (n) = mass of solute (m)/molar mass (M)
moles of NaCl = 87.75 g/58.55 g.mol-1 = 1.499 moles
Therefore,
Molarity of NaCl = 1.499 moles/0.5 L = 2.998 moles/lit ≅ 3 M
<u>Ans: (D)</u>
