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2 years ago

12

How is matter conserved in a chemical reaction

2 answers:

belka [17]2 years ago

7 0

"Both the initial and final substances are composed of atoms because all matter<span> is composed of atoms. According to the law of conservation of </span>matter<span>, </span>matter<span> is neither created nor destroyed, so we must have the same number and type of atoms after the </span>chemical<span> change as were present before the </span>chemical<span> change." therefore, that is how matter is conserved </span>

frez [133]2 years ago

7 0

Matter is changed in a way that it can not be changed back to it's original form. The other answerer basically described a physical reaction.

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Consider the following reaction:

Kitty [74]

Answer : The value of equilibrium constant (Kc) is, 0.0154

Explanation :

The given chemical reaction is:

$SO_2Cl_2(g)\rightarrow SO_2(g)+Cl_2(g)$

Initial conc. $2.4\times 10^{-2}$ 0 0

At eqm. $(2.4\times 10^{-2}-x)$ x x

As we are given:

Concentration of $Cl_2$ at equilibrium = $1.3\times 10^{-2}M$

That means,

$x=1.3\times 10^{-2}M$

The expression for equilibrium constant is:

$K_c=\frac{[SO_2][Cl_2]}{[SO_2Cl_2]}$

Now put all the given values in this expression, we get:

$K_c=\frac{(x)\times (x)}{2.4\times 10^{-2}-x}$

$K_c=\frac{(1.3\times 10^{-2})\times (1.3\times 10^{-2})}{2.4\times 10^{-2}-1.3\times 10^{-2}}$

$K_c=0.0154$

Thus, the value of equilibrium constant (Kc) is, 0.0154

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2 years ago

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Olenka [21]

The third answer because there are two of each atom

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Llana [10]

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Answer:

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