To solve this problem we use Boyle's law to correlate the varying volume and pressure at constant temperature. Assuming ideal gas law, we use the equation P1/V1= P2/V2. Substituting, 735 mm Hg/ P2= 63.5 ml/69.2 ml. P2 is equivalent thus to 800.97 mm Hg.
First, we need to find the atomic mass of

.
According to the periodic table:
The atomic mass of Carbon = C = 12.01
The atomic mass of Hydrogen = H = 1.008
The atomic mass of Oxygen = O = 16
As there are 6 Carbons, 12 Hydrogens and 6 Oxygens, therefore:
The
molar mass of

= 6 * 12.01 + 12 * 1.008 + 6 * 16
The
molar mass of

= 180.156
grams/moleNow that we have the molar mass of

, we can find the grams of glucose by using:
mass(of glucose in grams) = moles(of glucose given in moles) * molar mass(in grams/mole)
Therefore,
mass(of glucose in grams) = 2.47 * 180.156
mass(of glucose in grams = 444.99 grams
Ans: Mass of glucose in grams in 2.47 moles =
444.99 grams
-i
1) molar mass of the C6H8O<span>6, you need to consult the atomic weight of the C, H and O atoms that are in the periodic table: C is 12; H is 1; O is 16
(12x6)+(1x8)+(16x6)= 176g/mol
</span><span>176 g = 1 mol
0,5 g = x mol 500mg= 0,5 grams
molar mass = mass÷ moles
176 = 0,5÷ x
x= 2,84 x 10⁻³ mol
2) To find the number of molecules present in those </span>2,84 x 10⁻³ mol we need to multiple the moles by the <span>Avogadro's constant
No. of molecules = Avogadro's constant x n° of moles
</span>No. of molecules = 6.022 x 10²³ x 2,84 x 10⁻³ <span>
= 1.71 x 10²¹ molecules of vit C. </span>
Hmmm... Water? It's not an element. it's made of two so it's bi and not compound. It's not pure because it disperse and evaporates under heat. Pure substances are more like metals