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Luda [366]
3 years ago
6

A solution of ammonia NH3(aq) is at equilibrium. How would the equilibrium

Chemistry
1 answer:
alina1380 [7]3 years ago
4 0

<u>Answer:</u> The equilibrium will shift in the direction of NH_3

<u>Explanation:</u>

The chemical equation for the aqueous solution of ammonia follows:

NH_3+H_2O\rightleftharpoons NH_4^++OH^-

According to Le-chtelier's principle:

If there is any change in the variables of the reaction, then the equilibrium will shift in that direction of equilibrium to minimize the effect.

If we add more amount of NH_4^+ to the solution, more of the products will be present. But according to Le-chtelier's principle, to minimize this effect, the equilibrium will shift in the backward direction that in the direction of NH_3

Hence, the equilibrium will shift in the direction of NH_3

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How many moles are in a sample of 1.52 x 1024 atoms of mercury (Hg)?
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2.5 moles

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when avogadro's number = 6.02 * 10^23

and when 1 mole of the sample will give → 6.02*10^23 atoms

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How many atoms are in 3.2 pg of Ca? The molar mass of Ca is 40.08<br> g/mol.
anyanavicka [17]

Answer:

4.81×10¹⁰ atoms.

Explanation:

We'll begin by converting 3.2 pg to Ca to grams (g). This can be obtained as follow:

1 pg = 1×10¯¹² g

Therefore,

3.2 pg = 3.2 pg × 1×10¯¹² g / 1 pg

3.2 pg = 3.2×10¯¹² g

Therefore, 3.2 pg is equivalent to 3.2×10¯¹² g

Next, we shall determine the number of mole in 3.2×10¯¹² g of Ca. This can be obtained as follow:

Mass of Ca = 3.2×10¯¹² g

Molar mass of Ca = 40.08 g/mol

Mole of ca=.?

Mole = mass /molar mass

Mole of Ca = 3.2×10¯¹² / 40.08

Mole of Ca = 7.98×10¯¹⁴ mole.

Finally, we shall determine the number of atoms present in 7.98×10¯¹⁴ mole of Ca. This can be obtained as illustrated below:

From Avogadro's hypothesis,

1 mole of Ca contains 6.02×10²³ atoms.

Therefore, 7.98×10¯¹⁴ mole of Ca will contain = 7.98×10¯¹⁴ × 6.02×10²³ = 4.81×10¹⁰ atoms.

Therefore, 3.2 pg of Ca contains 4.81×10¹⁰ atoms.

7 0
3 years ago
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