Data Given:
Pressure = P = 0.5 atm
Volume = V = 2.0 L
Temperature = T = 50 °C + 273 = 323 K
Moles = n = ?
Solution:
Let suppose the gas is acting Ideally, Then According to Ideal Gas Equation.
P V = n R T
Solving for n,
n = P V / R T
Putting Values,
n = (0.5 atm × 2.0 L) ÷ (0.0821 atm.L.mol⁻¹.K⁻¹ × 323 K)
n = 0.0377 mol
There are two valence electrons in a single atom of magnesium.
The transitions which fall to the lowest principle position release the greatest energies. In this case, this would be the transition from the 5p to the 3s orbital (a Paschen transition).
Hope this helps!