If we ignore air resistance, a falling body will fall 16t2 feet in t seconds. What is the average velocity between t
1 answer:
Answer:
<em>262.4 m/s</em>
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Explanation:
The complete question is
If we ignore air resistance, a falling body will fall 16t^2 feet in t seconds. What is the average velocity between t=8 and t=8.4? Round your answer to two decimal places if necessary.
The distance fallen s = 16t^2
The velocity v = = 32t
If we substitute the values of t into the velocity v, we'll have
at t = 8 s, V1 = 32 x 8 = 256 m/s
at t = 8.4 s, V2 = 32 x 8.4 = 268.8 m/s
Average velocity = (V2 - V1)/2 = (268.8 + 256)/2 = <em>262.4 m/s</em>
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