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3 years ago

If we ignore air resistance, a falling body will fall 16t2 feet in t seconds. What is the average velocity between t

Physics

1 answer:

erik [133]3 years ago

7 0

Answer:

262.4 m/s

Explanation:

The complete question is

If we ignore air resistance, a falling body will fall 16t^2 feet in t seconds. What is the average velocity between t=8 and t=8.4? Round your answer to two decimal places if necessary.

The distance fallen s = 16t^2

The velocity v = $\frac{ds}{dt}$ = 32t

If we substitute the values of t into the velocity v, we'll have

at t = 8 s, V1 = 32 x 8 = 256 m/s

at t = 8.4 s, V2 = 32 x 8.4 = 268.8 m/s

Average velocity = (V2 - V1)/2 = (268.8 + 256)/2 = 262.4 m/s

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3 years ago

At the same instant that a 0.50-kg ball is dropped from 25 m above Earth, a second ball, with a mass of 0.25 kg, is thrown strai

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Answer:

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Substituting in equation s = ut + 0.5 at²

s = 15 x 2 - 0.5 x 9.81 x 2² = 10.38 m

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We have equation for center of gravity

$\bar{x}=\frac{m_1x_1+m_2x_2}{m_1+m_2}$

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x₂ = 10.38 m

Substituting

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3 years ago

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Answer:

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