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3 years ago

When popcorn is heated over a flame, the kernel burst open. why does this occur?

1 answer:

4 0

<span>If you faced the situation when popcorn is heated over a flame and the kernel burst opened the thing which caused that is definitely : the air and water vapor which remain in the kernell have expanded.
Hope that helps.

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10. Mario is making chocolate. In part of the chocolate-making process, he changed the phase from a liquid to a solid. What happ

Naily [24]

Answer:

Explanation:

in a liquid the particles are widespread and move around each other but in a solid they move in place and are tightly packed

6 0

3 years ago

A mass on a horizontal surface is connected to the spring and pulled to the right along the surface stretching the spring by 25

solniwko [45]

Answer:

320 N/m

Explanation:

From Hooke's law, we deduce that

F=kx where F is applied force, k is spring constant and x is extension or compression of spring

Making k the subject of formula then

$k=\frac {F}{x}$

Conversion

1m equals to 100cm

Xm equals 25 cm

25/100=0.25 m

Substituting 80 N for F and 0.25m for x then

$k=\frac {80}{0.25}=320N/m$

Therefore, the spring constant is equal to 320 N/m

3 0

3 years ago

When a roller coaster gets to the bottom of a descent, describe the energy transfers and changes to energy stores that happen if

Feliz [49]

Answer:

its B

Explanation:

It's B & A at the same time because A. a roller coaster uses brakes to slow down and stop. B is the most reasonable answer. Because all roller coasters go up and over a second time over the hill, but they also slow down. But go with B.

TELL ME IF I´M RITE

6 0

2 years ago

If it requires 8.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re

jenyasd209 [6]

Answer:

The amount of work done required to stretch spring by additional 4 cm is 64 J.

Explanation:

The energy used for stretching spring is given by the relation :

$E = \frac{1}{2}kx^{2}$ .......(1)

Here k is spring constant and x is the displacement of spring from its equilibrium position.

For stretch spring by 2.0 cm or 0.02 m, we need 8.0 J of energy. Hence, substitute the suitable values in equation (1).

$8 = \frac{1}{2}\timesk\times k \times(0.02)^{2}$

k = 4 x 10⁴ N/m

Energy needed to stretch a spring by 6.0 cm can be determine by the equation (1).

Substitute 0.06 m for x and 4 x 10⁴ N/m for k in equation (1).

$E = \frac{1}{2}\times4\times10^{4}\times (0.06)^{2}$

E = 72 J

But we already have 8.0 J. So, the extra energy needed to stretch spring by additional 4 cm is :

E = ( 72 - 8 ) J = 64 J

7 0

3 years ago

A person jogs at an average velocity of 3 m/s West. How long will it take this person to run a 30-meter city block?

grigory [225]

Answer:

It will take the person 10 seconds to run a 30-meter city block.

Explanation:

To solve this problem, we must remember the formula for velocity:

velocity = displacement/time

If we plug in the values that we are given, we get:

3 m/s = 30 m/time

We can see from the above equation that our answer should be in seconds, so we can get rid of the units to simplify the equation slightly.

3 = 30/t

Next, we can multiply both sides by t:

3t = 30

Then, we should divide both sides of the equation by 3 to get the variable t alone on the left side of the equation.

t = 10

Therefore, the correct answer is 10 s.

8 0

3 years ago

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