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Gekata [30.6K]
3 years ago
11

When popcorn is heated over a flame, the kernel burst open. why does this occur?

Physics
1 answer:
Bezzdna [24]3 years ago
4 0
<span>If you faced the situation when  popcorn is heated over a flame and the kernel burst opened the thing which caused that is definitely : the air and water vapor which remain in the kernell have expanded.
Hope that helps.

</span>
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(1) Explain : Market and its characteristics.​
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market is a place where we sell or buy things ( goods)

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I need help, ASAP, I know what thermal energy is, but how does a skater use it when on the track?
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Answer: Looked it up but

Explanation:

When the skater lands on the track, the vertical component of his kinetic energy is converted to thermal energy. You can do experiments where there is no loss to thermal energy (only PE and KE conversions) by turning friction off and by making sure the skater doesn't leave the track.

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Calculating the Mass of a Granite Monument
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Answer:

m = 684,865,8 g

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The 9 kg block is then released and accelerates to the right, toward the 5 kg block. The surface is rough and the coefficient of
Ahat [919]

Complete Question

The complete question is shown on the first and second uploaded image

Answer:

The velocity is  =4.51m/s  

Explanation:

The kinetic energy of the 9 kg can be determined by these expression

        Kinetic energy of 9 kg  block = initial energy stored - energy lost as a result of friction

  Now to obtain the initial energy stored

               Let U denote the initial energy stored and

                      U  = \frac{1}{2} kx^2

Where x  is the length the spring is displaced

k is the force constant of the string

         U = \frac{1}{2} * 627 * (0.6)^2

          = 112.86 J

   Now referring to the formula above

i.e          Kinetic energy of 9 kg  block = initial energy stored - energy lost as a result of friction

                \frac{1}{2} mv^2 = 112.86 - \mu_kmgx

                v^2 = \frac{2(112.86 -\mu_kmgx)}{m}

                v = \sqrt{\frac{2(112,86- \mu_kmgx)}{m}}

and we are told that coefficient of friction  = 0.4 and the mass is 9 kg ,the acceleration due to gravity = 9.8m/s^2  this displacement length of spring = 0.6

  Therefore   v = \sqrt{\frac{2(112.86- (0.4 *9*9.8*0.6))}{9} }

                        =4.51m/s      

           

8 0
3 years ago
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