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igor_vitrenko [27]
4 years ago
7

Which of the following are examples of plasma?

Chemistry
2 answers:
artcher [175]4 years ago
4 0
The answers are "t<span>ails of comets, the ionosphere, and a neon sign." or options A, D, and E. Tails of comments are mainly made of plasma. Ice cubes are examples of a solid. A gas fire key word gas is example of a gas. The ionosphere is also mainly made of plasma. A neon sign uses plasma in order to work. A flashlight uses a light bulb which isn't a example of plasma therefore  thats a no.

Hope this helps!
</span>
QveST [7]4 years ago
4 0

Which of the following are examples of plasmas?


ice cubes


tails of comets


a gas fire


the ionosphere


a neon sign


a flashlight


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What are some shared properties of both transition metals and alkali metals.
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Both transition metals and alkali metals are good conductors of heat and electricity, react with water, and are easily oxidized.

<h3>What are alkali metals and transition metals?</h3>

The alkali metals are elements of group 1 which are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), caesium (Cs), and francium (Fr).  They are also known as the s-block elements because they have their outermost electron in an s-orbital.

The alkali metals are shiny, soft, highly reactive metals and readily lose their outermost electron to create cations with charge +1. They can tarnish rapidly in the air due to oxidation by atmospheric moisture and oxygen.

Transition elements or transition metals are elements that have partially filled d-orbitals. An element having a d-subshell that is partially filled with electrons or can form stable cations with an incompletely filled d orbital.

Any element present in the d-block of the modern periodic table which consists of groups 3 to 12, is considered to be a transition element. For example, the mercury in the +2 oxidation state, corresponds to an electronic configuration of (n-1)d¹⁰. Many paramagnetic compounds are formed by transition metals because they have unpaired electrons in the d orbital.

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Answer:

KOH(aq) + HCl(aq) ——-> KCl(aq) + H2O(l)

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