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2 years ago

Which situation describes the highest rate of power

Physics

2 answers:

krok68 [10]2 years ago

8 0

Answer:

B. An engine does 100 joules of work in 2 seconds.

Explanation: I hope u get it right.

Andreyy892 years ago

8 0

Answer: A king

Explanation: A king has a everything he needs to live as long as he lives

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The main difference between obsessive-compulsive personality disorder (OCPD) and obsessive-compulsive disorder (OCD) is that ___

maksim [4K]

Answer:

B. people with OCD know their disorder is irrational

Explanation:

Got it right

6 0

2 years ago

Read 2 more answers

When a firecracker explodes, what types of energy does it give off?

fomenos

The answer is c.
Sound, light and heat energy.

Hope this helped :)

7 0

2 years ago

Starting from rest, how far will a brick fall if it is going 15 m/s and accelerates at a rate of 9.8 m/s2?

masha68 [24]

Answer:

11.48 m

Explanation:

A brick starts from rest and gains a speed of 15 m/s and accelerates at 9.8 m/s^2

u = 0

v= 15

a= 9.8

s= ?

V^2 = U^2 + 2as

15^2 = 0^2 + 2 × 9.8×s

225= 19.6s

s= 225/19.6

s = 11.48m

Hence the brick will fall 11.48 m

7 0

3 years ago

What is difference between magnetic flux and magnetic flux linkage?

Anika [276]

Answer:

Magnetic flux has formular: BA while Magnetic flux linkage has formula: NBA

Explanation:

N is number of turns of a coil

B is magnetic flux density across the coil

A is area of coil

$.$

7 0

2 years ago

A uniform disk of mass M = 4.9 kg has a radius of 0.12 m and is pivoted so that it rotates freely about its axis. A string wrapp

AlekseyPX

Answer:

(A) 2.4 N-m

(B) $0.035kgm^2$

(D) 1741.13 J

(E) 725.481 rad

Explanation:

We have given mass of the disk m = 4.9 kg

Radius r = 0.12 m, that is distance = 0.12 m

Force F = 20 N

(a) Torque is equal to product of force and distance

So torque $\tau =Fr$ , here F is force and r is distance

So $\tau =20\times 0.12=2.4Nm$

(B) Moment of inertia is equal to $I=\frac{1}{2}mr^2$

So $I=\frac{1}{2}\times 4.9\times 0.12^2=0.035kgm^2$

Torque is equal to $\tau =I\alpha$

So angular acceleration $\alpha =\frac{\tau }{I}=\frac{2.4}{0.035}=68.571rad/sec^2$

So initial angular speed $\omega _{0}=0rad/sec$

Time t = 4.6 sec

From first equation of motion we know that $\omega =\omega _0+\alpha t$

So $\omega =0+68.571\times 4.6=315.426rad/sec$

(D) Kinetic energy is equal to $KE=\frac{1}{2}I\omega ^2=\frac{1}{2}\times 0.035\times 315.426^2=1741.13J$

(E) From second equation of motion

$\Theta =\omega _0t+\frac{1}{2}\alpha t^2=0\times 4.6+\frac{1}{2}\times 68.571\times 4.6^2=725.481rad$

3 0

3 years ago