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Answer:
The nearest plant (A) receives 4 times more radiation from the farthest plant
Explanation:
The energy emitted by the star is distributed on the surface of a sphere, whereby intensity received is the power emitted between the area of the sphere
I = P / A
P = I A
The area of the sphere is
A = 4π r²
Since the amount of radiation emitted by the star is constant, we can write this expression for the position of the two planets
P = I₁ A₁ = I₂ A₂
I₁ / I₂ = A₂ / A₁
Suppose index 1 corresponds to the nearest planet,
r2 = 2 r₁
I₁ / I₂ = r₁² / r₂²
I₁ / I₂ = r₁² / (2r₁)²
I₁ / I₂ = ¼
4 I₁ = I₂
The nearest plant (A) receives 4 times more radiation from the farthest plant
In finding the distance that covers we simply add the three km which is
12 + 4 + 1 = 17km
17 km is the distance they cover.
We are going to use the displacement formula which is
d = vt + 1/2 at^2
d = 11.7 km
11.7 is the displacement
Answer:
Explanation:
Let suppose that centrifuge is rotating at constant angular speed, which means that resultant acceleration is equal to radial acceleration at given radius, whose formula is:
Where:
- Angular speed, measured in radians per second.
- Radius of rotation, measured in meters.
The angular speed is first determined:
Where 
is the angular speed, measured in revolutions per minute.
If 
, the angular speed measured in radians per second is:
Now, if 
and 
, the resultant acceleration is then:
If gravitational acceleration is equal to 9.807 meters per square second, then the radial acceleration is equivalent to 1006.382 times the gravitational acceleration. That is:
