Answer:
the speed of the cheetah at the end of the 3 seconds is: 19.5 m/s
Explanation:
Let's use the equation that relates speed with acceleration:
vf = vi + a * t
where vf stands for final velocity, vi stands for initial velocity, a for acceleration, and t for the time acceleration is applied. Then, in our case we have:
vf = 0 + 6.5 (3)
vf = 19.5 m/s
Considering the unknown resistence as R and using the Ohm's First Law, we have:
The equivalent resistence is given by the resistor series with the lamp resistence.
If you notice any mistake in my english, please let me know, because i am not native.
Answer:
The motorcycle travelled 69.73 m during these 3.1 s.
Explanation:
In order to calculate the distance that the motorcycle travelled we first need to obtain the acceleration rate that was used to brake the vehicle. We do that by using the following formula:
a = (V_final - V_initial)/(t) = (15 - 30)/(3.1) = -4.84 m/s^2
The distance is given by the following formula:
S = (V_final^2 - V_initial^2)/(2*a)
S = (15^2 - 30^2)/[2*(-4.84)] = (225 - 900)/(-9.68) = -675/(-9.68) = 69.73 m
The motorcycle travelled 69.73 m during these 3.1 s.