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vodomira [7]
3 years ago
6

An electromagnetic wave has a frequency of 5.0 x 1014 Hz. What is the

Physics
1 answer:
andrezito [222]3 years ago
5 0

Answer:

c

Explanation:

wavelength = speed of light/ frequency

= (3x 10^8 m/s)/(5.0 x 10^14 Hz)

= 6.0 x 10^-7 m

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A circular loop of wire has radius of 9.50 cmcm. A sinusoidal electromagnetic plane wave traveling in air passes through the loo
m_a_m_a [10]

Answer:

The induced emf  is  \epsilon  = 0.1041 \  V  

Explanation:

From the question we are told that

   The  radius of the circular loop is  r =  9.50 \ cm  =  0.095 \ m

     The  intensity of the wave is  I  =  0.0215 \ W/m^2

      The wavelength is  \lambda =  6.90\ m

Generally the intensity is mathematically represented as

         I  =  \frac{ c *  B^2  }{ 2 * \mu_o  }

Here  \mu_o is the permeability of free space with value  

         \mu_o  =  4 \pi *10^{-7} N/A^2

B is the magnetic field which can be mathematically represented from the equation as

          B  =  \sqrt{ \frac{ 2 *  \mu_o  *  I  }{ c} }

substituting values

          B  =  \sqrt{ \frac{ 2 *  4\pi *10^{-7} *   0.0215  }{ 3.0*10^{8}} }

          B  =  1.342 *10^{-8} \  T

The  area is mathematically represented as

       A =  \pi r^2

substituting values

       A =  3.142 *   (0.095)^2

       A = 0.0284

The angular velocity is mathematically represented as

        w =  2 *  \pi  *  \frac{c}{\lambda }

substituting values          

       w =  2 *  3.142   *  \frac{3.0*10^{8}}{ 6.90 }  

        w =  2.732 *10^{8} rad  \ s^{-1}  

Generally the induced emf is mathematically represented as

        \epsilon  =  N *  B  *  A  *  w * sin (wt )

At maximum induced emf  sin (wt)  =  1

    So

         \epsilon  =  N *  B  *  A  *  w

substituting values

         \epsilon  = 1  *    1.342 *10^{-8}   *  0.0284  *2.732 *10^{8}  

         \epsilon  = 0.1041 \  V  

         

7 0
3 years ago
A mass is oscillating with amplitude A at the end of a spring.
Dmitry_Shevchenko [17]

A) x=\pm \frac{A}{2\sqrt{2}}

The total energy of the system is equal to the maximum elastic potential energy, that is achieved when the displacement is equal to the amplitude (x=A):

E=\frac{1}{2}kA^2 (1)

where k is the spring constant.

The total energy, which is conserved, at any other point of the motion is the sum of elastic potential energy and kinetic energy:

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2 (2)

where x is the displacement, m the mass, and v the speed.

We want to know the displacement x at which the elastic potential energy is 1/3 of the kinetic energy:

U=\frac{1}{3}K

Using (2) we can rewrite this as

U=\frac{1}{3}(E-U)=\frac{1}{3}E-\frac{1}{3}U\\U=\frac{E}{4}

And using (1), we find

U=\frac{E}{4}=\frac{\frac{1}{2}kA^2}{4}=\frac{1}{8}kA^2

Substituting U=\frac{1}{2}kx^2 into the last equation, we find the value of x:

\frac{1}{2}kx^2=\frac{1}{8}kA^2\\x=\pm \frac{A}{2\sqrt{2}}

B) x=\pm \frac{3}{\sqrt{10}}A

In this case, the kinetic energy is 1/10 of the total energy:

K=\frac{1}{10}E

Since we have

K=E-U

we can write

E-U=\frac{1}{10}E\\U=\frac{9}{10}E

And so we find:

\frac{1}{2}kx^2 = \frac{9}{10}(\frac{1}{2}kA^2)=\frac{9}{20}kA^2\\x^2 = \frac{9}{10}A^2\\x=\pm \frac{3}{\sqrt{10}}A

3 0
3 years ago
If the baseball and the plastic ball were moving at the same speed which ball would hit a bat harder
Lerok [7]
A baseball would hit the bat harder. This is because the baseball is a lot heavier and more dense than the plastic ball. The keyword that you're looking for is density. The baseball is dense.
7 0
3 years ago
Earth is about 93 million miles from the Sun but only 239,000 miles from the Moon. Likewise, the Sun has a mass that is over 20
Yakvenalex [24]

Answer:

Gravity is dependent on the mass of two bodies and the distance between them. There is a strong gravitational attraction between Earth and the Moon because they’re relatively close to one another. There is a strong gravitational attraction between Earth and the Sun because the Sun is so massive

7 0
2 years ago
A moving small car has a head-on collision with a large stationary truck 7.3 times the mass of the car. Which statement is true
san4es73 [151]

Answer:

The car would speed off 2x's as fast as the speed of the heavy truck provided the the collision is an elastic collision where there's no or little friction occurring within the scenario.

Explanation:

Newton's law proves that an object with a greater mass can move objects of lesser mass at greater distances and speed.

7 0
3 years ago
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