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3 years ago

An electromagnetic wave has a frequency of 5.0 x 1014 Hz. What is the

Physics

1 answer:

andrezito [222]3 years ago

5 0

Answer:

Explanation:

wavelength = speed of light/ frequency

= (3x 10^8 m/s)/(5.0 x 10^14 Hz)

= 6.0 x 10^-7 m

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Gas A has molecules with small mass. Gas B has molecules with larger mass. They are at the same temperature.

Julli [10]

Answer:

c)The gases have the same average kinetic energy.

Explanation:

As we know that the kinetic energy of gas is given as

$K = \frac{1}{2}mv^2$

here we know that

$v = \sqrt{\frac{3RT}{M}}$

so we have

$K = \frac{1}{2}m (\frac{3RT}{M})$

now we have

$K = \frac{3}{2}n RT$

now mean kinetic energy per molecule is given as

$K_{avg} = \frac{3}{2}KT$

so this is independent of the mass of the gas

so average kinetic energy will remain same for both the gas molecules

6 0

3 years ago

Calculate the kinetic energy of a 10kg cart traveling at 4 m/s?

ycow [4]

Answer:

Explanation:

Ke = 1/2mv2 = 1/2.10.(4)2=5.16= 80 J

5 0

3 years ago

Read 2 more answers

After leaving the end of a ski ramp, a ski jumper lands downhill at a point that is displaced 68.3 m horizontally from the end o

inessss [21]

Answer:

a)52.58 m/s

b)56.13°

Explanation:

assume the upward direction as positive

x-component of the velocity = 29.3×cos33.6°=24.40 m/s (remain constant)

y-component of the velocity which is -29.3sin33.6°= -16.21 m/s

time of flight = 68.3/24.40= 2.7991 seconds

now, we can obtain final velocity in y-direction

$v_f_y= v_i_y-gt$

$v_f_y=-16.21-(-9.8)×2.7991$

=43.66 m/s

$v_0=\sqrt{29.3^2+43.66^2}$

=52.58 m/s

for direction

$tan^{-1}\frac{43.66}{29.3}$

56.13° from the horizontal

3 0

3 years ago

A small car with mass of 0.800 kg travels at a constant speed

Alexandra [31]

Answer:

The equation of equilibrium at the top of the vertical circle is:

\Sigma F = - N - m\cdot g = - m \cdot \frac{v^{2}}{R}

The speed experimented by the car is:

\frac{N}{m}+g=\frac{v^{2}}{R}

v = \sqrt{R\cdot (\frac{N}{m}+g) }

v = \sqrt{(5\,m)\cdot (\frac{6\,N}{0.8\,kg} +9.807\,\frac{kg}{m^{2}} )}

v\approx 9.302\,\frac{m}{s}

The equation of equilibrium at the bottom of the vertical circle is:

\Sigma F = N - m\cdot g = m \cdot \frac{v^{2}}{R}

The normal force on the car when it is at the bottom of the track is:

N=m\cdot (\frac{v^{2}}{R}+g )

N = (0.8\,kg)\cdot \left(\frac{(9.302\,\frac{m}{s} )^{2}}{5\,m}+ 9.807\,\frac{m}{s^{2}} \right)

N=21.690\,N

7 0

2 years ago

Between 1911 and 1990, the top of the leaning bell tower at Pisa, Italy, moved toward the south at an average rate of 1.2 mm/y.T

Anit [1.1K]

Answer:

Angular speed, $\omega=6.90\times 10^{-13}\ rad/s$

Explanation:

It is given that,

The top of the leaning bell tower at Pisa, Italy, moved toward the south at an average rate of, v = 1.2 mm/yr

$1\ mm/yr=3.171\times 10^{-11}\ m/s$

Velocity, $v=3.80\times 10^{-11}\ m/s$

Height of the tower, h = 55 m

The height of the tower is equivalent to the radius. Let $\omega$ is the angular speed of the tower’s top about its base. The relation between the angular speed and the angular speed is given by :

$v=r\omega$

$\omega=\dfrac{v}{r}$

$\omega=\dfrac{3.80\times 10^{-11}\ m/s}{55\ m}$

$\omega=6.90\times 10^{-13}\ rad/s$

So, the average angular speed of the tower’s top about its base is $6.90\times 10^{-13}\ rad/s$ . Hence, this is the required solution.

6 0

3 years ago