How would I write in point slope form equation of the line that passes through (-1,-1) and (1,5)?

Mathematics

2 answers:

tatyana61 [14]3 years ago

7 0

Y+1=3(x+1)
if you need to simplify to slope intercept form then y=3x+2

77julia77 [94]3 years ago

6 0

$\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1})\qquad
(\stackrel{x_2}{1}~,~\stackrel{y_2}{5})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-(-1)}{1-(-1)}\implies \cfrac{5+1}{1+1}\cfrac{6}{2}\implies 3
\\\\\\
\begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-(-1)=3[x-(-1)]\implies y+1=3(x+1)$

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