Answer:
Females = 17 and males = 23
Step-by-step explanation:
Given that,
Total no of students in the class = 40
Let no. of females = x
No. of males = 6+x
ATQ,
Total students = males + females
40 = x+6+x
40-6 = 2x
34 = 2x
x = 17
Hence, there are 17 females and (6+17= 23) males.
Answer:
80 + 18i
Step-by-step explanation:
i² = -1
x = i + 9
x² = (i + 9)²
Applying; (a + b)² = a² + 2ab + b² concept,
x² = i² + 18i + 81
We know that i² = -1
So x² = -1 + 18i + 81
x² = 81 - 1 + 18i = 80 + 18i
The present age of mother and her daughter respectively are; 40 and 10 years respectively.
<h3>How to Solve Algebra Word Problems?</h3>
Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
Read more about Algebra Word Problems at; brainly.com/question/21405634
#SPJ1
Answer:
v' (0.5,1) , u' (0,1) , t' (-0.5,0) , w' (-0.5, -1)
Answer:
The answer would be X=2 .
Step-by-step explanation:
Hope it helps u :)
