Please help asap. 55 points

Mathematics

2 answers:

telo118 [61]2 years ago

8 0

$k^2+kf-2f^2$
= $k^2+kf-f^2-f^2$
= $k^2-f^2+kf-f^2$
= $(k+f)(k-f)+f(k-f)$
= $(k+2f)(k-f)$
B

atroni [7]2 years ago

5 0

The answer would be B. Using the foil method to check, the two k's equal k^2, then the k and -f would equal -fk, plus the 2fk would equal a positive fk. Lastly, the 2f and -f would equal -2f^2.

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While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between

aleksandr82 [10.1K]

Answer:

The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.

Step-by-step explanation:

Let the random variable X denote the water depths.

As the variable water depths is continuous variable, the random variable X follows a continuous Uniform distribution with parameters a = 2.00 m and b = 7.00 m.

The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$