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BaLLatris [955]
3 years ago
8

g The pump inlet is located 1 m above an arbitrary datum. The pressure and velocity at the inlet are 100 kPa and 2 m/s, respecti

vely. The pump exit is located 4 m above the same datum. The pressure and velocity are 500 kPa and 3 m/s, respectively. How much power is required to drive this pump assuming and efficiency of 75%
Engineering
1 answer:
oee [108]3 years ago
4 0

Answer:

The power needed to drive this pump assuming  and efficiency of 75% is 1874.0 watts (W)

Explanation:

Solution:

Given that:

Velocity  = 2 m/s

Pressure = 100 kPa

The pump exit is =4 m

Efficiency 75%

Thus,

We apply the method called the Bernoulli's equation between two reservoirs

p₁ / ps + v₁²/2g + z₁

=p₂/ps/v₂²/2g +z₂ + hL

The density of gasoline (pg) is = 680 kg m³

The gravity of acceleration is known to be  =9.81 m/s²

So,

100/680 *9.81 + 2²/2 *9.81 + 1 = 500/ 680 * 9.81 + 3²/2 * 9.81 +4 + hL

16. 2 = 79.41 + hL

hl =79.41 - 16.2

hL =63.21 m

the unit weight of gasoline is(γ) = 680 * 9.81 = 6670.8 m/s

Now we find the efficiency

The efficiency  (η) = The output power /Input power

Where hL =H

The input power = γ * Q * H/0.75

=6670.8 *12/3600 * 63.21

=6670.8 * 0.333 * 63.21

=6670.8 *0.2107

=1405.5/0.75

The input power =1874.0 Watts

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A hydraulic cylinder is to be used to move a workpiece in a manufacturing operation through a distance of 50 mm in 10 s. A force
svetlana [45]

Answer:

The answer to this question is 1273885.3 ∅

Explanation:

<em>The first step is to determine the required  hydraulic flow rate liquid if working pressure and  if a cylinder with a piston diameter of 100 mm is available.</em>

<em>Given that,</em>

<em>The distance = 50mm</em>

<em>The time t =10 seconds</em>

<em>The force F = 10kN</em>

<em>The piston diameter is = 100mm</em>

<em>The pressure = F/A</em>

<em> 10 * 10^3/Δ/Δ </em>

<em> P = 1273885.3503 pa</em>

<em>Then</em>

<em>Power = work/time  = Force * distance /time</em>

<em> = 10 * 1000 * 0.050/10</em>

<em>which is  =50 watt</em>

<em>Power =∅ΔP</em>

<em>50 = 1273885.3 ∅</em>

5 0
3 years ago
A labor-intensive process to manufacture a product has a fixed cost of $338,000 and a variable cost of $143 per unit. An automat
ozzi

Answer:

no of unit is 17941

Explanation:

given data

fixed cost = $338,000

variable cost = $143 per unit

fixed cost = $1,244,000  

variable cost = $92.50 per unit

solution

we consider here no of unit is = n

so here total cost of labor will be sum of fix and variable cost i.e

total cost of labor = $33800 + $143 n  ..........1

and

total cost of capital intensive  = $1,244,000 + $92.5 n   ..........2

so here in both we prefer cost of capital if cost of capital intensive less than cost of labor

$1,244,000 + $92.5 n  <  $33800 + $143 n

solve we get

n > \frac{906000}{50.5}

n > 17941

and

cost of producing less than selling cost so here

$1,244,000 + $92.5 n < 197 n

solve it we get

n > \frac{1244000}{104.5}  

n > 11904

so in both we get greatest no is 17941

so no of unit is 17941

3 0
3 years ago
A 0.25in diameter steel rod BC is securely attached between two identical 1in diameter copper rods (AB and CD). Find the torque
Helen [10]

Answer:

Tmax= 46.0 lb-in

Explanation:

Given:

- The diameter of the steel rod BC d1 = 0.25 in

- The diameter of the copper rod AB and CD d2 = 1 in

- Allowable shear stress of steel τ_s = 15ksi

- Allowable shear stress of copper τ_c = 12ksi

Find:

Find the torque T_max

Solution:

- The relation of allowable shear stress is given by:

                             τ = 16*T / pi*d^3

                             T = τ*pi*d^3 / 16

- Design Torque T for Copper rod:

                             T_c = τ_c*pi*d_c^3 / 16

                             T_c = 12*1000*pi*1^3 / 16

                             T_c = 2356.2 lb.in

- Design Torque T for Steel rod:

                             T_s = τ_s*pi*d_s^3 / 16

                             T_s = 15*1000*pi*0.25^3 / 16

                             T_s = 46.02 lb.in

- The design torque must conform to the allowable shear stress for both copper and steel. The maximum allowable would be:

                             T = min ( 2356.2 , 46.02 )

                             T = 46.02 lb-in

6 0
3 years ago
Scenario* The organization is a regional XYZ Credit Union/Bank that has multiple branches and locations throughout the region.*
fiasKO [112]

Answer:

1) For preparation of plan :

It is to gather the team and creating the timeline. Gathering the inputs for the plan and confirming the mission and vision then launching the strategy.

2) A mission would describe about the company and the specification of the company

A vision is the long term or future state of the organization to achieve in a time frame.

Both would include the OAS statements and strategic shifts.

3) The OAS and strategic shift would help to create a balanced score card that would help for data gathering and analysis

This would include the financial, customers goal, Process goals, people's goals etc.

4) To create and develop the plan's framework:

To set the objective for high level organizational goals

To measure the and accomplish the objectives

To take initiatives to achieve the objectives

Explanation:

8 0
3 years ago
Two thousand pieces will flow through from the first machine A to the final machine F based on the given sequence of operations.
Vlad1618 [11]

The total number of trips that the vehicle has to make based on the given sequence of operation is 120 trips.

<em>"Your</em><em> </em><em>question is not complete, it seems to be missing the following information;"</em>

The sequence of operation is A - E - D - C - B - A - F

The given parameters;

  • <em>number of pieces that will flow from the first machine A to machine F, = 2,000 pieces</em>
  • <em>initial unit load specified in the first machine, L₁ = 50</em>
  • <em>final unit load, L₂ = 100 </em>
  • <em>the capacity of the vehicle = 1 unit load</em>

<em />

The given sequence of operation of the vehicle;

A - E - D - C - B - A - F

<em>the vehicle makes </em><em>6 trips</em><em> for </em><em>100</em><em> unit </em><em>loads</em>

The total number of trips that the vehicle has to make, in order to transport the 2000 pieces of the load given, is calculated as follows.

100 unit loads ----------------- 6 trips

2000 unit loads --------------- ?

= \frac{2000}{100} \times 6\\\\= 120 \ trips

Thus, the total number of trips that the vehicle has to make based on the given sequence of operation is 120 trips.

Learn more here:brainly.com/question/21468592

6 0
2 years ago
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