Problem definition

The beam is supported by a pin at A and a roller at B which has negligible weight and a radius of 15 mm. If the coefficient of s

Anettt [7]

Answer:

33.4

Explanation:

Step 1:

\sumMo=0 (moment about the origin)

Fb(15)-Fc(15)=0

Fb=Fc

Step 2:

\sumFx=0

-Fb-Fccos\theta+Ncsin\theta=0

Fc=0.3Nc=Fb

-0.3Nc-0.3Nccos\theta+Ncsin\theta=0

(-0.3-cos\theta+sin\theta)Nc=0----(1)

\sumFy=0

Nccos\theta+Fcsin\theta-Nb=0

Nccos\theta+0.3Ncsin\theta-Nc=0

Nc[cos\theta+0.3sin\theta-1]=0--------(2)

Solving eq (1) and eq (2)

\theta=33.4

Step 3:

As the roller is a two force member

2(90-\phi)+\theta=180

\phi=\theta/2

\phi=Tan(\muN/N)-1

\phi=16.7

\theta=2x16.7=33.4

5 0

3 years ago

Part A - Transmitted power A solid circular rod is used to transmit power from a motor to a machine. The diameter of the rod is

uranmaximum [27]

Answer:

Explanation:

Given that solid circular rod rotates at constant speed and neglecting losses throughout the system, power is calculated as the product of torque and angular speed. That is to say:

$\dot W = T \cdot \omega$

There is a formula that relates torque with shear stress:

$\tau = \frac{T \cdot D}{2 \cdot J}$

Where $J$ is the torsion module, whose formula for a solid circular cross section is:

$J = \frac{\pi \cdot D^{4}}{32}$

The tension module is calculated herein:

$J = 3.835 in^{4}$

Maximum allowed torsion is found by isolating it from shear stress equation:

$T_{max} = \frac{2 \cdot J \cdot \tau_{max}}{D}$

$T_{max} = 31.907 kip \cdot in\\T_{max} = 2.659 kip \cdot ft$

Then, maximum transmissible power is determined directly:

$\dot W = (2.659 kip \cdot ft) \cdot (2)\cdot (\pi) \cdot (170 rpm)\\\dot W \approx 2840.188 \frac{kip \cdot ft}{min} \\\dot W \approx 86.066 h.p.$

8 0

3 years ago

If x < 5 and x >c, give a value of c such that there

Arlecino [84]

we have

x<5

x>c

we know that

The solution is the intersection of both solution sets of the given inequalities.

The solutions of the compound inequality must be solutions of both inequalities.

The value of c could be 5 or any number greater than 5, such that there are no solutions to the compound inequality

Because

A number cannot be both less than 5 and greater than 5 at the same time

therefore

the answer is

for c_> there are no solutions to the compound inequality

7 0

3 years ago

Who was the American founder and leader of the Shakers in the 1770’s who advocated equality, individual responsibility, and peac

DaniilM [7]

Answer: Ann Lee (1736-1784)

Explanation:

6 0

3 years ago

Read 2 more answers

A farmer has 12 hectares of land on which he grows corn, wheat, and soybeans. It costs $4500 per hectare to grow corn, $6000 to

maw [93]

The number of hectares of each crop he should plant are; 250 hectares of Corn, 500 hectares of Wheat and 450 hectares of soybeans

<h3>How to solve algebra word problem?</h3>

He grows corn, wheat and soya beans on the farm of 1200 hectares. Thus;

C + W + S = 12 ----(1)

It costs $45 per hectare to grow corn, $60 to grow wheat, and $50 to grow soybeans. Thus;

45C + 60W + 50S = 63750 -----(2)

He will grow twice as many hectares of wheat as corn. Thus;

W = 2C ------(3)

Put 2C for W in eq 1 and eq 2 to get;

C + 2C + S = 1200

3C + S = 1200 -----(4)

45C + 60(2C) + 50S = 63750

45C + 120C + 50S = 63750

165C + 50S = 63750 ------(5)

Solving eq 4 and 5 simultaneosly gives;

C = 250 and W = 500

Thus; S = 1200 - 3(250)

S = 450

Read more about algebra word problems at; brainly.com/question/13818690

5 0

2 years ago