1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ValentinkaMS [17]
3 years ago
7

Consider a cylindrical specimen of some hypothetical metal alloy that has a diameter of 11.0 mm. A tensile force of 1550 N produ

ces an elastic reduction in diameter of 6.9 x 10^-4 mm. Compute the elastic modulus of this alloy, given that Poisson's ratio is 0.35.

Engineering
1 answer:
Natasha_Volkova [10]3 years ago
6 0

Answer:

See it in the pic.

Explanation:

See it in the pic.

You might be interested in
. Bơm kiểu piston tác dụng đơn có áp suất p=0,64 Mpa và lưu lượng Q=3,5 l/s. Xác định tốc độ quay của trục bơm và công suất của
Viktor [21]

Answer:

not understand language

4 0
3 years ago
Write a statement that calls the recursive method backwardsAlphabet() with parameter startingLetter.
Tcecarenko [31]

Recursion refers to the act of calling a function itself. With the use of this strategy, complex problems can be reduced to more manageable, simpler ones. Recursion might be a little challenging to comprehend. The best method to figure out how it works is to experiment with it.

<h3>How to write a programme by recursive method ?</h3>

The process of making a function call itself is known as recursion. With the use of this strategy, complex problems can be reduced to more manageable, simpler ones. Recursion might be a little challenging to comprehend. Experimenting with it is the most effective way to learn how it functions.

public class Recursive Calls {

public static void backwards Alphabet(char currLetter) {

if (currLetter == 'a') {

System.out.println(currLetter);

}

else {

System.out.print(currLetter + " ");

backwards Alphabet(--currLetter);

}

return;

}

public static void main (String [] args) {

char starting Letter = '-';

starting Letter = 'z';

// Your solution goes here

backwards Alphabet(starting Letter);

return;

}

}

To learn more about recursive method refer to :

brainly.com/question/24167967

#SPJ4

6 0
1 year ago
A BS of 5.43 ft is taken on a level rod at a 120-ft distance, and a FS of 8.76 ft is taken on the rod held 1,100 feet away.(a) W
jok3333 [9.3K]

Answer:

The answer is attached below

Explanation:

3 0
3 years ago
Side milling cutter is an example of ______ milling cutter.
dusya [7]

Answer:

special type

Explanation:

As per the classification of milling cutters. This cutter can handle deep and long open slots in a more comfortable manner, which increase the productivity.

6 0
2 years ago
Two common methods of improving fuel efficiency of a vehicle are to reduce the drag coefficient and the frontal area of the vehi
qaws [65]

Answer:

\Delta V = 209.151\,L, \Delta C = 217.517\,USD

Explanation:

The drag force is equal to:

F_{D} = C_{D}\cdot \frac{1}{2}\cdot \rho_{air}\cdot v^{2}\cdot A

Where C_{D} is the drag coefficient and A is the frontal area, respectively. The work loss due to drag forces is:

W = F_{D}\cdot \Delta s

The reduction on amount of fuel is associated with the reduction in work loss:

\Delta W = (F_{D,1} - F_{D,2})\cdot \Delta s

Where F_{D,1} and F_{D,2} are the original and the reduced frontal areas, respectively.

\Delta W = C_{D}\cdot \frac{1}{2}\cdot \rho_{air}\cdot v^{2}\cdot (A_{1}-A_{2})\cdot \Delta s

The change is work loss in a year is:

\Delta W = (0.3)\cdot \left(\frac{1}{2}\right)\cdot (1.20\,\frac{kg}{m^{3}})\cdot (27.778\,\frac{m}{s})^{2}\cdot [(1.85\,m)\cdot (1.75\,m) - (1.50\,m)\cdot (1.75\,m)]\cdot (25\times 10^{6}\,m)

\Delta W = 2.043\times 10^{9}\,J

\Delta W = 2.043\times 10^{6}\,kJ

The change in chemical energy from gasoline is:

\Delta E = \frac{\Delta W}{\eta}

\Delta E = \frac{2.043\times 10^{6}\,kJ}{0.3}

\Delta E = 6.81\times 10^{6}\,kJ

The changes in gasoline consumption is:

\Delta m = \frac{\Delta E}{L_{c}}

\Delta m = \frac{6.81\times 10^{6}\,kJ}{44000\,\frac{kJ}{kg} }

\Delta m = 154.772\,kg

\Delta V = \frac{154.772\,kg}{0.74\,\frac{kg}{L} }

\Delta V = 209.151\,L

Lastly, the money saved is:

\Delta C = \left(\frac{154.772\,kg}{0.74\,\frac{kg}{L} }\right)\cdot (1.04\,\frac{USD}{L} )

\Delta C = 217.517\,USD

4 0
3 years ago
Other questions:
  • The arm of the robot is extending at a constant rate = 1.5 ft/s when r = 3 ft, z = (4t2) ft, and  = (1.5 t) rad, where t is in
    14·1 answer
  • Oil with a specific gravity of 0.72 is used as the indicating fluid in a manometer. If the differential pressure across the ends
    6·1 answer
  • Practice Problem: Large-Particle CompositesThe mechanical properties of a metal may be improved by incorporating fine particles
    5·1 answer
  • 1 kg of saturated steam at 1000 kPa is in a piston-cylinder and the massless cylinder is held in place by pins. The pins are rem
    5·1 answer
  • 9.21 A household oven door of 0.5-m height and 0.7-m width reaches an average surface temperature of 32℃ during operation. Estim
    8·1 answer
  • I need solution fast plesss​
    9·1 answer
  • A _______ contact allows current to flow when the switch's operator is not activated.?
    6·1 answer
  • Drag each label to the correct location on the table. Match to identify permanent and temporary structures.
    15·1 answer
  • The following is a series of questions pertaining to the NSPE Code of Ethics. Please indicate whether the statement are true or
    14·1 answer
  • Technician A says that synthetic blend oil has the same service life as that of full synthetic oils. Technician B says that conv
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!