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ValentinkaMS [17]

3 years ago

7

Consider a cylindrical specimen of some hypothetical metal alloy that has a diameter of 11.0 mm. A tensile force of 1550 N produ

ces an elastic reduction in diameter of 6.9 x 10^-4 mm. Compute the elastic modulus of this alloy, given that Poisson's ratio is 0.35.

1 answer:

Natasha_Volkova [10]3 years ago

6 0

Answer:

See it in the pic.

Explanation:

See it in the pic.

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A gas flows through a one-inlet, one-exit control volume operating at steady state. Considering an adiabatic control volume with

Hunter-Best [27]

Answer:

b. equal to the specific entropy of the gas at the inlet.

Explanation:

Isentropic process is the process in which the entropy of the system remains unchanged. The word isentropic is formed from the combination of the prefix "iso" which means "equal" and the word entropy.

If a process is completely reversible, without the need to provide energy in the form of heat, then the process is isentropic.

3 0

3 years ago

Find a negative feedback controller with at least two tunable gains that (1) results in zero steady state error when the input i

IceJOKER [234]

Answer:

Gc(s) = $\frac{0.1s + 0.28727}{s}$

Explanation:

comparing the standard approximation with the plot attached we can tune the PI gains so that the desired response is obtained. this is because the time requirement of the setting is met while the %OS requirement is not achieved instead a 12% OS is seen from the plot.

attached is the detailed solution and the plot in Matlab

8 0

3 years ago

If it took 2 hours to clean 4 houses how many houses could be cleaned in 3 hours

Lena [83]

Answer:

6 houses

Explanation:

because

2hrs=4 houses which means you are cleaning 2houses in one hour

so in 3 hours you will houses because you will clean 2 houses in one hour

I hope this helped you sorry if I am wrong

6 0

3 years ago

BTSAUDY5 NAME STARTS FROM THIS

otez555 [7]

Answer:

What's your question?

Explanation:

I'm not able to understand it....

Sorry.

7 0

3 years ago

Read 2 more answers

A circular bar will be subjected to an axial force (P) of 2000 lbf. The bar will be made of material that has a strength (S) of

schepotkina [342]

Answer:

$n = 2.36$

Explanation:

The stress experimented by the circular bar is:

$\sigma = \left[\frac{2000\, lbf}{\frac{\pi}{4}\cdot (0.5\,in)^{2}}\right]\cdot \left(\frac{1\,kpsi}{1000\,psi} \right)$

$\sigma = 10.186\,kpsi$

The safety factor is:

$n = \frac{24\,kpsi}{10.186\,kpsi}$

$n = 2.36$

5 0

3 years ago