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IgorLugansk [536]
3 years ago
11

What is 850,238x286,493?

Mathematics
1 answer:
Eddi Din [679]3 years ago
6 0

Answer:

243,58,723,5,334 i'm not really good at putting ,'s in the right place.

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What does a sample space look like?
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A sample space is a collection or a set of possible outcomes of a random experiment. The sample space is represented using the symbol, “S”. The subset of possible outcomes of an experiment is called events. A sample space may contain a number of outcomes that depends on the experiment

Hope this helps even a little bit:)

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An airplane must clear a 60-foot pole at the end of a runway 500 yards long determine the angle of elevation at which the airpla
Marat540 [252]

Answer:

2.3 degrees.      

Step-by-step explanation:

Please find the attachment.

We are told that an airplane must clear a 60-foot pole at the end of a runway 500 yards long.

Let us convert 500 yards to feet.

1 yard= 3 feet.

500 yards= 3*500 feet= 1500 feet.

We can see from our attachment pole and runway are in form of a right triangle. The pole is opposite to angle of elevation of plane and length of runway is adjacent.

Since tangent represents the relation between opposite and adjacent of right triangle, So we will use tangent to find angle of elevation that plane must ascend to clear the pole.  

tan(\theta)=\frac{60}{1500}    

\theta=\tan^{-1}(\frac{60}{1500} )

\theta=\tan^{-1}(0.04)

\theta=2.290610042639

Therefore, the airplane must ascend 2.3 degrees to clear the pole.

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3 years ago
PLEASE HELP - Which statement could be an interpretation of the graph’s x-intercept or y-intercept?
kozerog [31]
Its the third option on E2020
4 0
3 years ago
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Ok whoever answers this correct will get 100 brainly points
Snezhnost [94]

Answer:

We are given an area and three different widths and we need to determine the corresponding length and perimeter.  

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The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards.  This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.

The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10.  This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.

Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.

<u><em>Hope this helps!</em></u>

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