All categories

4 years ago

If the percent (mass/mass) for a solute is 8% and the mass of the solution is 200 g, what is the mass of solute in solution?

Chemistry

2 answers:

anyanavicka [17]4 years ago

4 0

Answer:

16 grams

Explanation:

Mass = 200g

Solute = MassX

X = percentage

X = 0.08

Solute = 200grams x 0.08 = 16 grams

tatyana61 [14]4 years ago

3 0

Answer:

The answer to your question is 16 g

Explanation:

Data

Percent by mass = 8%

Mass of the solution = 200 g

Mass of solute = ?

Formula

Percent by mass = mass of solute / mass of solution x 100

- Solve for mass of solute

Mass of solute = Percent by mass x mass of solution / 100

- Substitution

Mass of solute = 8 x 200 / 100

- Simplification

Mass of solute = 1600 / 100

- Result

Mass of solute = 16 g

You might be interested in

Can someone solve this plz βeta decay carbon atomic mass 14 atomic # 6

nordsb [41]

Answer:

14/6C your welcome

Explanation:

8 0

3 years ago

What is the mass in grams of 2.25 mol of the element iron, Fe?

pochemuha

Answer:

126g

Explanation:

Data obtained from the question include:

Mole of Fe = 2.5moles

Molar Mass of Fe = 56g/mol

Mass of Fe =?

Number of mole = Mass/Molar Mass

Mass = number of mole x molar Mass

Mass of Fe = 2.25 x 56

Mass of Fe = 126g

Therefore, the mass in 2.25mol of Fe is 126g

5 0

3 years ago

Read 2 more answers

What advice would you give to a person who handles hydrogen and oxygen in their workplace?I think I have an idea of what advice

finlep [7]

Regard the principle of utilization of two gas.

Make a consistent control of hardware containing gas.

Make a consistent control of weight diminishing valves giving gas.

No smoking zone.

3 0

3 years ago

What is the molarity of a solution prepared by diluting 43.72 ml of 1.005 M aqueous K2CR2O7 to 500 ml

UNO [17]

Answer:

43.72

Explanation:

that is the answer hope u liked it and I did this already along time ago

3 0

3 years ago

The relationship between the molar concentration of silver ion in a saturated solution of silver phosphate and the solubility pr

kondor19780726 [428]

Answer: The solubility product of $Ag_3PO_4$ is $27s^4$

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as $K_{sp}$

$Ag_3PO_4\leftrightharpoons 3Ag^++PO_4^{3-}$

We are given:

Solubility of $Ag_3PO_4$ = S mol/L

By stoichiometry of the reaction:

1 mole of $Ag_3PO_4$ gives 3 moles of $Ag^{+}$ and 1 mole of $PO_4^{3-}$ .

When the solubility of $Ag_3PO_4$ is S moles/liter, then the solubility of $Ag^{+}$ will be 3S moles\liter and solubility of $PO_4^{3-}$ will be S moles/liter.

Expression for the equilibrium constant of $Ag_2CrO_4$ will be:

$K_{sp}=[Ag^+]^3[PO_4^{3-}]$

$K_{sp}=[3s]^3[s]=27s^4$

The solubility product of $Ag_3PO_4$ is $27s^4$

8 0

3 years ago