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ser-zykov [4K]
3 years ago
11

If the percent (mass/mass) for a solute is 8% and the mass of the solution is 200 g, what is the mass of solute in solution?

Chemistry
2 answers:
anyanavicka [17]3 years ago
4 0

Answer:

16 grams

Explanation:

Mass = 200g

Solute = MassX

X = percentage

X = 0.08

Solute = 200grams x 0.08 = 16 grams

tatyana61 [14]3 years ago
3 0

Answer:

The answer to your question is  16 g

Explanation:

Data

Percent by mass = 8%

Mass of the solution = 200 g

Mass of solute = ?

Formula

Percent by mass = mass of solute / mass of solution x 100

- Solve for mass of solute

  Mass of solute = Percent by mass x mass of solution / 100

- Substitution

   Mass of solute = 8 x 200 / 100

- Simplification

    Mass of solute = 1600 / 100

- Result

    Mass of solute = 16 g

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= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778

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= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556

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