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3 years ago

15

How do you think future generations will meet their demands for energy? i'll give u a thanks

2 answers:

OverLord2011 [107]3 years ago

3 0

From what they are doing now to what they have said is put wind turbines in the oceans as well as use more river waters and tide dams to produce energy for homes and businesses around the area

faltersainse [42]3 years ago

3 0

They will have to cut down on there use of energy or use more renewable energy sources. They could use solar panels, wind turbines, nuclear power, hydroelectricity, geothermal energy or tidal power. It depends on the weather and temperature where they live.

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The reaction is at dynamic equilibrium.

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Answer:

Nitrogen and hydrogen combine at the same rate that ammonia breaks down.

Explanation:

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3 years ago

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It's true that mechanical waves require a medium for transmission.

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3 years ago

A horizontal 745 N merry-go-round of radius

Arturiano [62]

Answer:

The kinetic energy of the merry-goround after 3.62 s is 544J

Explanation:

Given :

Weight w = 745 N

Radius r = 1.45 m

Force = 56.3 N

To Find:

The kinetic energy of the merry-go round after 3.62 = ?

Solution:

Step 1: Finding the Mass of merry-go-round

$m = \frac{ weight}{g}$

$m = \frac{745}{9.81 }$

m = 76.02 kg

Step 2: Finding the Moment of Inertia of solid cylinder

Moment of Inertia of solid cylinder I = $0.5 \times m \times r^2$

Substituting the values

Moment of Inertia of solid cylinder I

=> $0.5 \times 76.02 \times (1.45)^2$

=> $0.5 \times 76.02\times 2.1025$

=> $79.91 kg.m^2$

Step 3: Finding the Torque applied T

Torque applied T = $F \times r$

Substituting the values

T = $56.3 \times 1.45$

T = 81.635 N.m

Step 4: Finding the Angular acceleration

Angular acceleration , $\alpha = \frac{Torque}{Inertia}$

Substituting the values,

$\alpha = \frac{81.635}{79.91}$

$\alpha = 1.021 rad/s^2$

Step 4: Finding the Final angular velocity

Final angular velocity , $\omega = \alpha \times t$

Substituting the values,

$\omega = 1.021 \times 3.62$

$\omega = 3.69 rad/s$

Now KE (100% rotational) after 3.62s is:

KE = $0.5 \times I \times \omega^2$

KE = $0.5 \times 79.91 \times 3.69^2$

KE = 544J

6 0

4 years ago

Helppppp me please guys

Kisachek [45]

B maybe I'm not for sure tho lol so if u get it wrong I'm sorry lol

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3 years ago

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Morgarella [4.7K]

Answer:

2030

Explanation:

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3 years ago

Read 2 more answers