2. The force between charges is 7 N. The distance between the charges is 4 x 10-6 m. If one of the charges is 2 x 10-8 C, what i
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The equilibrium conditions allow to find the results for the balance forces are:
- F₁ = 225.4 N
- F₂ = 558.6 N
When the acceleration is zero we have the equilibrium conditions for both linear and rotational motion.
∑ F = 0
∑ τ = 0
Where F are the forces and τ the torques.
The torque is the product of the force and the perpendicular distance to the point of support,
The free-body diagrams are diagrams of the forces without the details of the bodies, see attached for the free-body diagram of the system.
We write the translational equilibrium condition.
F₁ - W₁ - W₂ + F₂ = 0
We write the equation for the rotational motion, set our point of origin at scale 1, and the counterclockwise turns are positive.
F₂ 2 - W₁ 1 - W₂ 1.5 = 0
Let's calculate F₂
F₂ =
F₂ = (m g + M g 1.5)/ 2
F₂ =
F₂ = 558.6 N
We substitute in the translational equilibrium equation.
F₁ = W₁ + W₂ - F₂
F₁ = (m + M) g - F₂
F₁ = (12 +68) 9.8 - 558.6
F₁ = 225.4 N
In conclusion using the equilibrium conditions we can find the forces of the balance are:
- F₁ = 225.4 N
- F2 = 558.6 N
Learn more here: brainly.com/question/12830892
Given data:
* The mass of the baseball is 0.31 kg.
* The length of the string is 0.51 m.
* The maximum tension in the string is 7.5 N.
Solution:
The centripetal force acting on the ball at the top of the loop is,
For the maximum velocity of the ball at the top of the vertical circular motion,
where g is the acceleration due to gravity,
Substituting the known values,
Thus, the maximum speed of the ball at the top of the vertical circular motion is 4.16 meters per second.