The "Standard Atmosphere" is 760 mm Hg .
2.13 times that pressure is (2.13 x 760) = 1,618.8 mm Hg.
Explanation:
Given that,
Mass of a body, m = 1 kg
Force constant, k = 16 N/m
We need to find the angular frequency and the frequency of oscillation.
(a) The angular frequency of a body is given by :
(b) The frequency of oscillation is given by :
Hence, this is the required solution.
Answer:
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Explanation:
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Answer:
Magnitude of induced emf is 0.00635 V
Explanation:
Radius of circular loop r = 45 mm = 0.045 m
Area of circular loop
Magnetic field is increases from 250 mT to 350 mT
Therefore change in magnetic field
Emf induced is given by
Magnitude of induced emf is equal to 0.00635 V
Answer:
1.
109.6 cm , - 1.74 , real
2.
1.5
Explanation:
1.
d₀ = object distance = 63 cm
f = focal length of the lens = 40 cm
d = image distance = ?
using the lens equation
d = 109.6 cm
magnification is given as
m = - 1.74
The image is real
2
d₀ = object distance = a
d = image distance = - (a + 5)
f = focal length of lens = 30 cm
using the lens equation
a = 10
magnification is given as
m = 1.5