All categories

3 years ago

The equation NaCl →Na +Cl is a ______ reaction. A. decomposition B. single displacement C. synthesis

1 answer:

Citrus2011 [14]3 years ago

4 0

The correct answer is (a.) decomposition. The equation NaCl --> Na + Cl is a decomposition reaction. That is because the synthesis reaction looks like this Na + Cl = NaCl, and is the opposite of the decomposition. The decomposition reaction is the chemical reaction in which a single compound break into new compounds.

You might be interested in

Carbon dioxide in a piston-‐‐cylinder is expanded in a polytropic manner. The initialtemperature and pressure are 400 K and 550

Arisa [49]

Answer:

q_poly = 14.55 KJ/kg

Explanation:

Given:

Initial State:

P_i = 550 KPa

T_i = 400 K

Final State:

T_f = 350 K

Constants:

R = 0.189 KJ/kgK

k = 1.289 = c_p / c_v

n = 1.2 (poly-tropic index)

Find:

Determine the heat transfer per kg in the process.

Solution:

-The heat transfer per kg of poly-tropic process is given by the expression:

q_poly = w_poly*(k - n)/(k-1)

- Evaluate w_poly:

w_poly = R*(T_f - T_i)/(1-n)

w_poly = 0.189*(350 - 400)/(1-1.2)

w_poly = 47.25 KJ/kg

-Hence,

q_poly = 47.25*(1.289 - 1.2)/(1.289-1)

q_poly = 14.55 KJ/kg

4 0

3 years ago

A busy chipmunk runs back and forth along a straight line of acorns that has been set out between its burrow and a nearby tree.

dmitriy555 [2]

<u>Answer:</u>

Chipmunk's average acceleration during the 2.07 s time interval = 0.1256 $m/s^2$

<u>Explanation:</u>

We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

In this case we need to find acceleration value, we have initial velocity = 1.47 m/s, final velocity = 1.73 m/s and time taken = 2.07 seconds.

Substituting

1.73 = 1.47 + a * 2.07

a = 0.1256 $m/s^2$

Chipmunk's average acceleration during the 2.07 s time interval = 0.1256 $m/s^2$

7 0

4 years ago

In the long jump, an athlete launches herself at an angle above the ground and lands at the same height, trying to travel the gr

NikAS [45]

A) 2.64t

B) 2.64h

C) 2.64D

Explanation:

The motion of the athlete is equivalent to the motion of a projectile, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion (constant acceleration) along the vertical direction

The time of flight of a projectile can be found from the equations of motion, and it is found to be

$t=\frac{2u sin \theta}{g}$

where

u is the initial speed

$\theta$ is the angle of projection

g is the acceleration due to gravity

In this problem, when the athlete is on the Earth, the time of flight is $t$ .

When she is on Mars, the acceleration due to gravity is:

$g'=0.379 g$

where g is the acceleration due to gravity on Earth. Therefore, the time of flight on Mars will be:

$t'=\frac{2usin \theta}{g'}=\frac{2u sin \theta}{0.379g}=\frac{1}{0.379}t=2.64t$

The maximum height reached by a projectile can be also found using the equations of motion, and it is given by

$h=\frac{u^2 sin^2\theta}{2g}$

where

u is the initial speed

$\theta$ is the angle of projection

g is the acceleration due to gravity

In this problem, when the athlete is on the Earth, the maximum height is $h$ .

When she is on Mars, the acceleration due to gravity is:

$g'=0.379 g$

where g is the acceleration due to gravity on Earth. So, the maximum height reached on Mars will be:

$h'=\frac{u^2 sin^2\theta}{2g'}=\frac{u^2 sin^2\theta}{(0.379)2g}=\frac{1}{0.379}h=2.64h$

The horizontal distance covered by a projectile is also found from the equations of motion, and it is given by

$D=\frac{u^2 sin(2\theta)}{g}$

where:

u is the initial speed

$\theta$ is the angle of projection

g is the acceleration due to gravity

In this problem, when the athlete is on the Earth, the horizontal distance covered is D.

When she is on Mars, the acceleration due to gravity is:

$g'=0.379 g$

where g is the acceleration due to gravity on Earth. Therefore, the horizontal distance reached on Mars will be:

$D'=\frac{u^2 sin(2\theta)}{g'}=\frac{u^2 sin(2\theta)}{(0.379)g}=\frac{1}{0.379}D=2.64D$

7 0

4 years ago

Looking at the Helmholtz Coil apparatus from the front, the electron beam was directed to the right and then it curled into a co

natima [27]

Answer:

Explanation:

The magnetic field created by Helmholtz Coil apparatus is in right direction

3 0

3 years ago

The density of the gold is 19.3g/cm3.

elena55 [62]

If both nuggets have the same mass and different densities then it can be concluded that the volume with the highest density is smaller.

For, so to speak, density is a relation of how much mass is there in a given volume. So the more the mass and the smaller the volume, the greater the density.

To verify this, let us calculate the volumes of iron pyrite and gold pyrite.

For the iron pyrite nugget:

density = mass / volume

volume = mass / density

volume = 50/5

volume = 10cm3

For the gold nugget:

volume = mass / density

volume = 50 / 19.3

volume = 2.59cm3

Therefore it is found that the nugget with the highest density (gold) is the one with the lowest volume.

3 0

3 years ago