Answer:
The sum of the lengths of the sides is 2292 yards and the sum of the lengths of the triangle is 3056 yards
Explanation:
Since y represents the length of fence that is opposite (parallel) to the river and x represent the length of fence perpendicular to the river.
Therefore since we can use 3,056 yards of fencing
Side perpendicular to the river = x and,
Side opposite to the river = y = 3056 - 2x
The area of the rectangle formed (A) = Perpendicular side × Parallel side
∴ A = x(3056 - 2x) = 3056x - 2x²
A = 3056x - 2x²
To maximize the area, A' (dA/dx) = 0
∴ A' = 3056 - 4x = 0
3056 - 4x = 0
4x = 3056
x = 764 yards
y = 3056 - 2x = 3056 - 2(764) = 1528 yards.
Side perpendicular to the river = 764 yards and,
Side opposite to the river = 1528 yards
The sum of the lengths of the sides = 764 + 1528 = 2292 yard and the sum of the lengths of the triangle = 764 + 764 + 1528 = 3056 yards
The two components of projectile motion include the following:
<h3>What is a Projectile?</h3>
This is defined as a missile propelled by the application of an external force and allowed to move freely under the influence of gravity and air resistance.
The equation for Horizontal motion Vx = V * cos(α)
Vertical velocity component: Vy = V * sin(α)
Read more about Projectile here brainly.com/question/24216590
Answer:
6 Newtons to the left.
Explanation:
We can convert this into a generic algebra equation by giving directions positive and negative values.
The 6 will be positive, and the 10 and 2 will be negative.
Add 10 and 2 to have 12.
6-12 = -6.
Therefore you have 6 newtons to the left (negative).
Answer:
The magnitude of force per unit length of one wire on the other is
and the direction is away from one another
The magnitude of force per unit length of one wire on the other is
and the direction is towards each other.
Explanation:
= Vacuum permeability = 
= Current in first wire = 2.9 A
= Current in second wire = 5.3 A
r = Gap between the wires = 11 cm
Force per unit length

The magnitude of force per unit length of one wire on the other is
and the direction is away from one another

The magnitude of force per unit length of one wire on the other is
and the direction is towards each other.
Value of resistor = (12V) /(1.2 x 10^-3A)=10000ohms=10k ohms