Answer:
the block that starts moving first is block A
, fr = 1.625 N
, fr = 1.5 N
Explanation:
For this exercise we use Newton's second law, for which we take a reference system with the x axis parallel to the plane and the y axis perpendicular to the plane
X axis
fr- Wₓ = 0
fr = Wₓ
Axis y
N-
= 0
N = W_{y}
Let's use trigonometry to find the components of the weight
sin θ = Wₓ / W
Cos θ = W_{y} / W
Wₓ = W sin θ
W_{y} = W cos θ
Wₓ = 11 sin θ
W_{y} = 11 cos θ
The equation for friction force is
fr = μ N
We substitute
μ (W cos θ) = W sin θ
μ = tan θ
We can see that the system began to move the angle.
θ = tan⁻¹ μ
So the angles are
Block A θ = tan⁻¹ 0.15
θ = 8.5º
Block B θ = tan⁻¹ 0.26
θ = 14.6º
So the block that starts moving first is block A
The friction force is
Block A
fr = Wx = W sin θ
fr = 11 sin 8.5
fr = 1.625 N
Block B
fr = 6 sin 14.6
fr = 1.5 N
Answer:
change in temperature
Explanation:
just like a rock, if it is put in different temperatures, the different substance you get.
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Answer:
13950kg
Explanation:
If we make the system both railroad cars, we know that the momentum of the whole system doesn't change because the forces are internal.
Let a be the mass of the second car.
The original momentum is 9300*15 kg*m/s+ a*0 kg*m/s = 139500 kg*m/s
After sticking together, the momentum is (9300+a)kg*6m/s, which should be equal to 139500 kg*m/s
Therefore (9300+a)*6 = 139500
9300+a = 23250
a = 13950 kg