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Mashcka [7]
3 years ago
7

Solve for x and y algebraically:x + y = 8 and 3x + 2y = 21​

Physics
2 answers:
Kaylis [27]3 years ago
7 0

Explanation:

ans ...(5,3)..............

Feliz [49]3 years ago
4 0

Answer:

x = 5

y = 3

Explanation:

x + y = 8 and 3x + 2y = 21

Here We use Substitution Method

x + y = 8 ...(1)

3x + 2y = 21 ...(2)

From equation (1) we get

x + y = 8

x = 8 - y

Now the value of x = 8 - y in equation (2)

3(8 - y) + 2y = 21

24 - 3y + 2y = 21

- y = 21 - 24

y = 3

Then Put the value of y in equation (1)

x + (3) = 8

x + 3 = 8

x = 8 - 3

x = 5

Thus The value of x is 5 and y is 3

<h3><u>For</u><u> </u><u>Verification</u><u> </u><u>Only</u><u>:</u></h3>

x + y = 8

5 + 3 = 8

8 = 8

3x + 2y = 21

3(5) + 2(3) = 21

15 + 6 = 21

21 = 21

L.H.S = R.H.S

<u>-TheUnknown</u><u>Scientist</u>

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Andreas93 [3]

Answer:

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Explanation:

For this exercise we use Newton's second law, for which we take a reference system with the x axis parallel to the plane and the y axis perpendicular to the plane

X axis

       fr- Wₓ = 0

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Axis y

      N- W_{y} = 0

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Let's use trigonometry to find the components of the weight

     sin θ = Wₓ / W

     Cos θ = W_{y} / W

     Wₓ = W sin θ

     W_{y} = W cos θ

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The equation for friction force is

      fr = μ N

   

We substitute

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      μ = tan θ

We can see that the system began to move the angle.

         θ = tan⁻¹ μ

So the angles are

Block A      θ = tan⁻¹ 0.15

           θ = 8.5º

Block B      θ = tan⁻¹ 0.26

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So the block that starts moving first is block A

The friction force is

         

Block A

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         fr = 1.625 N

Block B

         fr = 6 sin 14.6

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3 years ago
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Answer:

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7 0
3 years ago
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- A 9,300 kg. railroad car traveling at a velocity of 15m/s strikes a second boxcar
VARVARA [1.3K]

Answer:

13950kg

Explanation:

If we make the system both railroad cars, we know that the momentum of the whole system doesn't change because the forces are internal.

Let a be the mass of the second car.

The original momentum is 9300*15 kg*m/s+ a*0 kg*m/s = 139500 kg*m/s

After sticking together, the momentum is (9300+a)kg*6m/s, which should be equal to 139500 kg*m/s

Therefore (9300+a)*6 = 139500

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a = 13950 kg

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4 years ago
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