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3 years ago

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Two charged spheres are 8.45 cm apart. They are moved, and the force on each of them is found to have been tripled. How far apar

t are they now?

1 answer:

Aleonysh [2.5K]3 years ago

4 0

Force between two charges is given by

$F = \frac{kq_1q_2}{r^2}$

here force is inversely depends on the square of the distance

so here if distance is decreased the force will increase'

now if force is tripled

$\frac{3F}{F} = \frac{r^2}{r'^2}$

initially distance between charges was 8.45 cm

$3 = \frac{8.45^2}{r'^2}$

$r' = \frac{8.45}{\sqrt3}$

$r' = 4.88 cm$

so the distance between charges is 4.88 cm now

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