Given two electrons with charge of 1.5x10^-10 m
The electostatic force between them is determined by this formula:
F = kq1q2/r^2
where
k = 9x10^9
q1 = q2 = 1.5x10^-10
r = 2.82x10^-15
F = 9x10^9 * (1.5x10^-10)^2 / 2.82x10^-15
= 71808.51
Answer:
A
Explanation:
A solution is homogeneous mixture composed of only one phase where a solute is dissolved into a solvent.
Answer:
Mass of sample in mg = 15,285 mg
Explanation:
Given:
Volume of urine sample = 15 ml
Density of sample = 1.019 g/ml
FInd:
Mass of sample in mg
Computation:
Mass = density x volume
Mass of sample in mg = Volume of urine sample x Density of sample
Mass of sample in mg = 1.019 x 15
Mass of sample in mg = 15.285 gram
Mass of sample in mg = 15.285 x 1,000
Mass of sample in mg = 15,285 mg
1) Cellulose - extracellular location, glycosidic bond, β-linkage. Cellulose is polysaccharide composed of glucose linked with β-1,4 bons.
2) Messenger RNA - informational macromolecule, phosphodiester bridge, helical structure possible, synthesis requires a template. mRNA is nucleic acid, <span> mRNA is </span>translated<span> into a polymer of amino acids.</span><span>
3) </span>Globular protein - peptide bond, helical structure possible, synthesis requires a template. Protein is composed of amino acid linked with peptide bond, secundary structure can be α-helix, gene expression.<span>
4) </span>Amylopectin - branched-chain polymer, glycosidic bond, helical structure possible. Amylopectin is subunit of starch, sugar with α-1,4 and α-1,6 glycosidic bonds.<span>
5) DNA - i</span>nformational macromolecule, phosphodiester bridge, helical structure possible, synthesis requires a template, nucleoside triphosphate. DNA is helical <span>chain of </span>nucleotides<span> carrying the </span>genetic<span> instructions.</span>
6) Fibrous protein - peptide bond, helical structure possible. Protein is composed of amino acid linked with peptide bond