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2 years ago

list all of the species that would have a net attraction to the positive charge: CH4, CH2Cl2, H3O+, H2O, C2H2Cl2, CO2, N3-,

1 answer:

4 0

A species with a positive charge will have a net attraction to a species with a negative charge. Among the choices, N3- is the only one attracted to a positive charge.

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HELP FAST!<br><br> 35 POINTS!<br><br> Why is flammability a chemical property?

Pavlova-9 [17]

Flammmability is a chemical change because it changes the composition of the object. the product is very different from the rectant.

8 0

2 years ago

You need a 70% alcohol solution. On hand, you have a 135 mL of a 20% alcohol mixture. You also have 85% alcohol mixture. How muc

frutty [35]

To obtain the desired solution:

450 mL of 85% alcohol solution is needed to obtain the desired solution.

Calculation:

Let x be the amount of the 85% alcohol required

The volume of the resulting 70% alcohol solution will then be = x + 135 ml

135 mL of the 20% alcohol solution contains the amount of "pure" alcohol is = 0.20×135 mL.

The 85% alcohol solution contains x mL of "pure" alcohol = 0.85× x mL.

The total amount of the "pure" alcohol is the sum

= 0.20×135 + 0.85× x mL.

It should be equal to the amount of the "pure" alcohol in the mixture, which is = 0.70× (x+135) ml.

So, your "pure alcohol" equation is,

= 0.85× x + 0.20×135 = 0.70× (x+135)

Simplify and solve it for x:

0.85x + 0.20×135 = 0.70x + 0.70×135,

0.85x - 0.70x = 0.70×135 - 0.20×135,

0.15x = 67.5

x = 67.5/0.15

= 450mL.

Learn more about the alcohol solution here,

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7 0

1 year ago

If oxygen is removed from a sample of air as iron rusts, what happens to the partial pressure of oxygen in the air? A it increas

anzhelika [568]

Bi did that test before

3 0

2 years ago

Read 2 more answers

20 cubic inches of a gas with an absolute pressure of 5 psi is compressed until its pressure reaches 10 psi. What's the new volu

belka [17]

10 cubic inches
We will use Boyle's law that states that for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional.
P1 V1 = P2 V2
Where
P1 is initial pressure = 5 psi
V1 is initial volume = 20 cubic inch
P2 is final pressure = 10 psi
V2 is final volume = unknown
V2 = P1,V1 / P2
V2 = 20 × 5 / 10
V2 = 100/10
V2 = 10 cubic inches

7 0

2 years ago

21 mL It required 42.35 mL of H2SO4 to neutralize 21.17 mL of 0.5000 M NaOH. Calculate the concentration of H2SO4

bija089 [108]

The balanced equation for the above reaction is
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of NaOH moles required-0.5000 M / 1000 mL/L x 21.17 mL = 0.010585 mol
According to stoichiometry, acid moles required are 1/2 of the base moles reacted
Therefore number of H₂SO₄ moles reacted - 0.010585 /2 mol
Number of moles in 42.35 mL of H₂SO₄ - 0.010585 /2 mol
Therefore in 1 L solution - (0.010585) /2 / 42.35 mL x 1000 mL/L = 0.125 M
Molarity of H₂SO₄ - 0.125 M

5 0

2 years ago