Answer: Mass Of CFC that needs to evaporate for the freezing of water = 328.24 g
Explanation: Heat gained by the CFC = Heat lost by water
Heat lost by water = Heat required to take water's temperature to 0°c + Heat required to freeze water at 0°c
Heat required to take water's temperature from 33°c to 0°c = mCΔT
m = 201g, C = 4.18 J/(gK), ΔT = 33
mCΔT = 201 × 4.18 × 33 = 27725.94 J
Heat required to freeze water at 0°c = mL
m = 201g, L = 334 J/g
mL = 201 × 334 = 67134 J
Heat gained by CFC to vaporize = mH = 27725.94 + 67134 = 94859.94 J
H = 289 J/g, m = ?
m × 289 = 94859.9
m = 328.24 g
QED!!
P1/T1=P2/T2 Gal Lussac's Law
25 C= 298K (just add 273)
0 C= 273 k
6.00atm/298=P2/273
P2=5.50 atm
Heat underneath the ground making its water boil
Explanation:
0 10 grams that that should be the answer
Answer: In equation of reaction nitrogen N2 is formed instead of O2
Formula of nitroglycerin is C3H5(NO3)3
Number for N2 is 12. Thus one mole nitroglycerin produces 3 moles N2
Explanation:
