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3 years ago

What is the mass of 12.3 moles of helium (He)?

Chemistry

1 answer:

anzhelika [568]3 years ago

6 0

Answer : The mass of 12.3 moles of helium (He) is, 49.2 grams.

Solution : Given,

Moles of helium = 12.3 moles

Molar mass of helium = 4 g/mole

Formula used :

$\text{Mass of helium}=\text{Moles of helium}\times \text{Molar mass of helium}$

$\text{Mass of helium}=(12.3mole)\times (4g/mole)=49.2g$

Therefore, the mass of 12.3 moles of helium (He) is, 49.2 grams.

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Answer:

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Explanation:

$N_2+3H_2\rightarrow 2NH_3$

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Initial rate of the reaction = R = $4.0\times 10^5 M/s$

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The initial rate of the reaction when concentration of hydrogen gas is doubled : R'

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3 years ago

At 333 k, which of the pairs of gases below would have the most nearly identical rates of effusion?

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d) M(NO₂)/M(N₂O₂) = 44/58= 0,758
e) M(CO)/M(N₂) = 28/28 = 1, CO and N₂ have iexact molecular masses and will effuse at nearly identical rates.

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Hello!

Answer:

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2 years ago

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Answer:

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