Answer: Yes, the mass of the reactants always equal to the mass of the products in a chemical reaction.
Explanation:
In a balanced chemical reaction, the mass of reactants is always equal to the mass of product that is a chemical reaction follows follows 'Law of Conservation of Mass'.
The law states that ' in a chemical reaction mass can neither be created nor be destroyed.
For example: 
Mass of the reactants = Mass of products

36 amu = 36 amu
Yes, the mass of the reactants always equal to the mass of the products in a chemical reaction.
Answer:
Exothermic, it obeys the law of conservation of energy
Explanation:
The reaction is an exothermic change. In this kind of change, heat is liberated to the surrounding. So the surrounding becomes hotter at the end of the heat change.
In chemical reactions that involves the loss of energy as heat, they obey the law of conservation of energy.
The law of conservation of energy states that energy is neither created nor destroyed but transformed from one form to another. In such reactions as this, chemical energy is transformed into heat energy.
Answer: 67.23 L
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
of particles.
To calculate the number of moles, we use the equation:
Putting in the values we get:
1 mole of methane occupies = 22.4 L
Thus 3 moles of methane occupy = 
Thus volume of 48 grams of methane gas is 67.23 L
The concentration of AlCl3 solution if 150 ml of the solution contains 550 mg of cl- ion is 0.0344 M
calculation
concentration = moles /volume in liters
volume in liters = 150 /1000= 0.15 L
number of moles calculation
write the equation for dissociation of Al2Cl3
that is AlCl3 ⇔ Al^3+ + 3 Cl ^-
find the moles of Cl^- formed
moles =mass/molar mass
mass in grams= 550/ 1000 =0.55 grams
molar mass of Cl^- =35.5 g/mol
moles is therefore= 0.55/35.5 =0.0155 moles
by use of mole ration betweem AlCl3 to Cl^- which is 1:3 the moles of AlCl3 is =0.0155 x 1/3= 5.167 x10^-3 moles
concentration of AlCl3 is therefore= 5.167 x10^-3/ 0.15 =0.0344 M
Idk how to write the formula I had this same question