3 years ago

What's the ratio 20:44

1 answer:

8 0

This becomes 10:22, then 5:11.

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levacccp [35]

I don't see the question . What is the question

3 0

2 years ago

Anna71 [15]

Answer:

thank you to your question i dont know if my

answer is correct this is my answer letter B

6 0

3 years ago

____ [38]

Let $z=-\sqrt3+i$ . Then

$|z|=\sqrt{(-\sqrt3)^2+1^2}=2$

$z$ lies in the second quadrant, so

$\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6$

So we have

$z=2e^{i5\pi/6}$

and the fourth roots of $z$ are

$2^{1/4}e^{i(5\pi/6+k\pi)/4}$

where $k\in\{0,1,2,3\}$ . In particular, they are

$2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}$

$2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}$

$2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}$

$2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}$

7 0

3 years ago

Alekssandra [29.7K]

(6,2) because X would equals 6 multiplied by 2 equals 12. Now minus 2 and that gives you a equilibrium of 10

3 0

3 years ago

xz_007 [3.2K]

It is going to be 41

5 0

3 years ago