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3 years ago

Which of these substances contains the most total atoms per molecule?

Chemistry

2 answers:

miss Akunina [59]3 years ago

6 0

C is your answer as it has 9 atoms

elixir [45]3 years ago

4 0

Answer: $Ni(NO_3)_2$

Explanation: A molecule is made up by combination of same atoms or different atoms.

1 molecule of $Na_2PFO_3$ consists of 2 atoms of sodium, 1 atom of phosphorous, 1 atom of flourine and three atoms of oxygen. Thus the total number of atoms is 7.

1 molecule of $H_2SO_4$ consists of 2 atoms of hydrogen, 1 atom of sulfur and 4 atoms of oxygen. Thus the total number of atoms is 7.

1 molecule of $Ni(NO_3)_2$ consists of 1 atom of nickel, 2 atoms of nitrogen and 6 atoms of oxygen. Thus the total number of atoms is 9.

1 molecule of $NbCl_5$ consists of 1 atom of niobium and 5 atoms of chlorine. Thus the total number of atoms is 6.

Thus substance which contains the most total atoms per molecule is $Ni(NO_3)_2$ .

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If an atom of the following element had a neutral charge, how many electrons would it have?

Yakvenalex [24]

Answer:

Explanation:

In order for an atom to have a neutral charge, it needs to have the same number of protons and electrons. You can see by the illustration that the atomic number is 31, so this element has 31 protons. Knowing that, we also know that it must have 31 electrons to be neutral.

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2 years ago

In a physical change, the _____ does not change.

Ksivusya [100]

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2 years ago

Which two scientists discovered the subatomic particles that make up the nucleus

bazaltina [42]

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6 0

2 years ago

Find the quantinum numbers n,m,l,s for the last of potassium layer pleasee help explain correctly all

Fantom [35]

Answer:

Quantum numbers of the outermost electron in potassium:

$n = 4$ .
$l = 1$ .
$m_l = 0$ .
Either $m_s = 1/2$ .

Explanation:

Refer to the electron configuration of a potassium atom. The outermost electron in a ground-state potassium atom is in the $4s$ orbital (fourth $s$ orbital.)

The quantum number $n$ (the principal quantum number) specifies the main energy shell of an electron. This electron is in the fourth main energy shell (as seen in the number four in the orbital.) Hence, $n = 4$ for this electron.

The quantum number $l$ (the angular momentum quantum number) specifies the shape ( $s$ , $p$ , $d$ , etc.) of an electron. $l = 1$ for $s\!$ orbitals (such as the one that contains this electron.

Quantum numbers $n$ and $l$ specify the shape of an orbital. On the other hand, the magnetic quantum number $m_l$ specifies the orientation of these orbitals in space.

However, $s$ orbitals are spherical. Regardless of the value of $n$ , the only possible $m_l$ value for electrons in $s\!$ orbitals is $m_l = 0$ .

The spin quantum number $m_s$ distinguishes between the two electrons in an orbital. The two possible values of $m_s \!$ are $(+1/2)$ and $(-1/2)$ . Typically, the first electron in an orbital is assigned an upward ( $\uparrow$ ) spin, which corresponds to $m_s = (+1/2)$ .