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4 years ago

Which of these substances contains the most total atoms per molecule?

Chemistry

2 answers:

miss Akunina [59]4 years ago

6 0

C is your answer as it has 9 atoms

elixir [45]4 years ago

4 0

Answer: $Ni(NO_3)_2$

Explanation: A molecule is made up by combination of same atoms or different atoms.

1 molecule of $Na_2PFO_3$ consists of 2 atoms of sodium, 1 atom of phosphorous, 1 atom of flourine and three atoms of oxygen. Thus the total number of atoms is 7.

1 molecule of $H_2SO_4$ consists of 2 atoms of hydrogen, 1 atom of sulfur and 4 atoms of oxygen. Thus the total number of atoms is 7.

1 molecule of $Ni(NO_3)_2$ consists of 1 atom of nickel, 2 atoms of nitrogen and 6 atoms of oxygen. Thus the total number of atoms is 9.

1 molecule of $NbCl_5$ consists of 1 atom of niobium and 5 atoms of chlorine. Thus the total number of atoms is 6.

Thus substance which contains the most total atoms per molecule is $Ni(NO_3)_2$ .

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Bess [88]

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3 years ago

What are the two parts of the third Step?

spin [16.1K]

Answer:

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3 years ago

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What is the minimum (non-zero) thickness of a benzene (n = 1.501) thin film that will result in constructive interference when v

ad-work [718]

Explanation:

At each reflecting surface (benzene and glass) there will be 180 degree phase change.

Now, for constructive interference the optical path in benzene is $\lambda$ .

Formula to calculate thickness of a benzene thin film is as follows.

Optical path length through benzene ( $\lambda$ ) = $2 \times n \times d$

Hence, substituting the given values into the above formula as follows.

Optical path length through benzene = $2 \times n \times d$

d = $\frac{\text{Optical path length through benzene}}{2 \times n}$

= $\frac{\lambda}{2 \times n}$

= $\frac{615 \times 10^{-9}}{2 \times 1.501}$ (as 1 nm = $10^{-9}m$

= 204.9 m

Thus, we can conclude that minimum thickness of benzene is 204.9 m.

4 0

3 years ago

The colligative molality of an unknown aqueous solution is 1.56 m.

yawa3891 [41]

Answer:

Vapor pressure of solution = 17.02 Torr

T° of boiling point for the solution is 100.79°C

T° of freezing point for the solution is -2.9°C

Explanation:

Let's state the colligative properties with their formulas

- Vapor pressure lowering

ΔP = P° . Xm . i

- Boiling point elevation

ΔT = Kb . m . i

- Freezing point depressión

ΔT = Kf . m . i

ΔP = Vapor pressure pure solvent (P°) - Vapor pressure solution

ΔT = T° boling solution - T° boiling pure solvent

ΔT = T° freezing pure solvent - T° freezing solution

i represents the Van't Hoff factor (ions dissolved in the solution). If we assume that the solute is non-volatile and the solution is ideal i = 1

Kf and Kb are cryoscopic and ebulloscopic constant, they are specific to each solvent.

Vapor pressure works with mole fraction (Xm) and the only data we have is molality, so we consider 1.56 moles of solute and 1000 g of solvent mass.

Moles of solvent → solvent mass / molar mass of solvent

Moles of solvent → 1000 g / 18 g/mol = 55.5 moles

Mole fraction is moles of solute / Total moles (mol st + mol sv)

Mole fraction: 1.56 / (1.56 + 55.5) = 0.027

- Vapor pressure lowering

ΔP = P° . Xm . i

17.5 Torr - Vapor pressure of solution = 17.5 Torr . 0.027 . 1

Vapor pressure of solution = - (17.5 Torr . 0.027 . 1 - 17.5 Torr)

Vapor pressure of solution = 17.02 Torr

- Boiling point elevation

ΔT = Kb . m . i

T° boiling solution - 100° = 0.512 °C/ m . 1.56 m . 1

T°boiling solution = 0.512 °C/ m . 1.56 m . 1 + 100°C

T°boiling solution = 100.79°C

- Freezing point depression

ΔT = Kf . m . i

0°C - T° freezing solution = 1.86 °C/m . 1.56 m . 1

T° freezing solution = - (1.86 °C/m . 1.56 m)

T° freezing solution = -2.9°C

3 0

4 years ago

What is the correct net ionic equation, including all coefficients, charges, and phases, for the following set of reactants?

andrezito [222]

Answer : The correct net ionic equation is:

$Ba^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow 2H_2O(l)+BaSO_4(s)$

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced molecular equation will be,

$Ba(OH)_2(aq)+H_2SO_4(aq)\rightarrow 2H_2O(l)+BaSO_4(s)$

The complete ionic equation in separated aqueous solution will be,

$Ba^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow 2H_2O(l)+BaSO_4(s)$

In this equation, spectator ions are not present.

The correct net ionic equation is:

$Ba^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow 2H_2O(l)+BaSO_4(s)$

8 0

3 years ago