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kotykmax [81]
3 years ago
5

How are compounds Similar to elements and how are they different​

Chemistry
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

A compound contains atoms of different elements chemically combined together in a fixed ratio. An element is a pure chemical substance made of same type of atom. Compounds contain different elements in a fixed ratio arranged in a defined manner through chemical bonds. They contain only one type of molecule.

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Which of the following is always a reactant in a combustion reaction? (5 points)
aleksandr82 [10.1K]

Answer:

A

Explanation:

Combustion reaction always has something hydrocarbon plus oxygen gas which equals to carbon dioxide and water. Always being a reactant in a combustion reaction is oxygen, since reactants are what we start off the reaction with.

4 0
3 years ago
What is the oxidation number for iodine in Mg(IO3)2 ?
navik [9.2K]
The oxidation number of iodine is 5 in Mg(IO3)2 which can be calculated as 
   Mg(IO3)2
   MgI2O6
As we know that
Mg has +2
O has -2
So,
   (+2) + 2I + 6 (-2)=0
   2 + 2I - 12 =0
   10+ 2I =0
    10 = 2I
     I =5

7 0
3 years ago
Read 2 more answers
Which atomic model proposed that electrons move in specific orbits around the nucleus of an atom
asambeis [7]
The Bohr Model, which was proposed by Niels Bohr in 1913

5 0
3 years ago
An aqueous solution has a mass of 490 grams containing 8.5 × 10-3 gram of calcium ions. The concentration of calcium ions in thi
Arada [10]
The concentration may be expressed as % m/m, this is the mass of ions in 100 mass units of solution, whose formula is:

% m/m = [mass of ions / mass of solution]*100

Then,

%m/m = [8.5*10^ -3 grams of calcium ions] / [490 grams of solution] * 100 =

% m/m = 1.74 * 10^ -5 %

Answer: 1.74 * 10 ^ -5 % 
5 0
4 years ago
Elimination of the pharmaceutical IV antibiotic gentamicin follows first-order kinetics. If the half-life of gentamicin is 1.5 h
Genrish500 [490]

Explanation:

The given data is:

The half-life of gentamicin is 1.5 hrs.

The reaction follows first-order kinetics.

The initial concentration of the reactants is 8.4 x 10-5 M.

The concentration of reactant after 8 hrs can be calculated as shown below:

The formula of the half-life of the first-order reaction is:

k=\frac{0.693}{t_1_/_2}

Where k = rate constant

t1/2=half-life

So, the rate constant k value is:

k=\frac{0.693}{1.5 hrs}

The expression for the rate constant is :

k=\frac{2.303}{t} log \frac{initial concentration}{concentration after time "t"}

Substitute the given values and the k value in this formula to get the concentration of the reactant after time 8 hrs is shown below:

\frac{0.693}{1.5 hrs} =\frac{2.303}{8 hrs} x log \frac{8.4x10^-^5}{y} \\ log \frac{8.4x10^-^5}{y} =1.604\\\frac{8.4x10^-^5}{y}=10^1^.^6^0^4\\\frac{8.4x10^-^5}{y}=40.18\\y=\frac{8.4x10^-^5}{40.18} \\=>y=2.09x10^-^6

Answer: The concentration of reactant remains after 8 hours is 2.09x10^-6M.

5 0
3 years ago
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